Question

Develop a Java program that prompts the user to enter her birth year (e.g. 1980). The program then uses the current year (i.e. 2020) and displays age of the user (i.e. 40). The program should handle any exception that can occur due to the value entered by the user.

Answer 1

//Program to calculate the age

import java.util.Scanner; //importing scanner class for taking input
public class Main //Main class
{
   public static void main(String[] args) { //Main method
   int x=0,age,currentYear=2020; //initialising variables
   Scanner input= new Scanner(System.in);
       System.out.print("Enter the year of Birth: ");   
       try{ //taking input under try block to handle Exception
       x=input.nextInt(); //taking input from User
       }
       catch(Exception InputMismatchException){ //handling Exception by catch
       System.out.println("\n Invalid Input by User!!");
       System.exit(0); //exiting program
       }
       if (x>currentYear){ //this will handle if year of birth entered is greaterthen currentYear
       System.out.println("Year of birth cannot be greater than "+currentYear);
       System.exit(0); //exiting program
       }
       age=currentYear-x; //calculating age
       if(age==0){ //if year of birth is currentYear
       System.out.println("Age is under 1 year");
       }
       else{
       System.out.println("Age is: "+age); //Showing age
       }
  
   }
}

coding and output screen:

OUTPUT: