In: Finance
The demand for widgets has been determined to be
10,000 per year. Each widget sells for $4.00 and
costs $2.25 to produce. Using breakeven analysis
and an interest rate of 12%, determine the maximum
purchase price that could be paid for the required
machinery. The machine is expected to last 8 years and
to have a salvage value of 5% of the purchase price.
Please show the answer in excel if possible
Cash Flow from Widget selling for year = No. of widgets * (Selling price - Cost price)
= 10,000 * ($4.00 - $2.25)
= $17,500
Present Value of Cash Flow for 8 years = $17,500 * PV factor @12% for 8 years
= $17,500 * [1 - (1+12%)^-8] / 12%
= $17,500 * 0.596116772 / 0.12
= $86,933.6958
Let Value of Machinery = X
Salvage value = X* 5% = 0.05X
Present Value of Salvage Value = 0.05X / (1+12%)^8 = 0.0201941614 X
At break even point Value of Machinery would be equal to Present Value of Cash Flows and Salvage Value
X = $86,933.6958 + 0.0201941614 X
0.979805839 X = $86,933.6958
X = $88,725.4314
Therefore, value of the machinery is $88,725.43
Calculation of NPV of the Project | |||||||||
Particulars | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Initial Investment | |||||||||
Cost of Machinery (A) | -X | ||||||||
Operating Cash Flows | |||||||||
Sales Revenue (B = 10,000 * $4) | 40000 | 40000 | 40000 | 40000 | 40000 | 40000 | 40000 | 40000 | |
Cost of Production (C = 10,000 * $2.25) | 22500 | 22500 | 22500 | 22500 | 22500 | 22500 | 22500 | 22500 | |
Cash Flow from Production (D = B-C) | 17500 | 17500 | 17500 | 17500 | 17500 | 17500 | 17500 | 17500 | |
Terminal Value | |||||||||
Salvage Value (E = -A*5%) | 0.05X | ||||||||
Total Cash Flows (F = A+D+E) | -X | 17500 | 17500 | 17500 | 17500 | 17500 | 17500 | 17500 | 17500 +0.05X |
Discount Factor @12% (G) 1/(1+12%)^n n=0,1,2,3,4,5,6,7,8 |
1 | 0.8928571 | 0.7971939 | 0.7117802 | 0.6355181 | 0.567427 | 0.506631 | 0.452349 | 0.403883228 |
Discounted Cash Flows (H = F*G) | -X | 15625.0000 | 13950.8929 | 12456.1543 | 11121.5664 | 9929.9700 | 8866.0446 | 7916.1113 |
7067.95649 + 0.020194161X |
NPV | -X + 86933.6959 + 0.020194161X | ||||||||
At break even point, NPV is Zero | |||||||||
-X + $86,933.6958 + 0.0201941614 X = 0 | |||||||||
0.979805839 X = $86,933.6958 | |||||||||
X = $88,725.4314 | |||||||||
Therefore, value of the machinery is $88,725.43 |