In: Statistics and Probability
Marital Status and Drinking
Drinks per Month |
||
Marital Status |
Abstain 1-20 |
20-40 40-60 over 60 |
Single |
67 230 |
84 96 87 |
Married |
411 633 |
149 85 102 |
Widowed |
85 61 |
17 90 89 |
Divorced |
47 90 |
25 102 156 |
Perform a hypothesis to decide whether there is an association between marital status and alcohol consumption.
Solve using Excel in the following manner:
ACTUAL | ||||||||||
Abstain | 1-20 | 20-40 | 40-60 | Over 60 | Total | |||||
Single | 67 | 230 | 84 | 96 | 87 | 564 | ||||
Married | 411 | 633 | 149 | 85 | 102 | 1380 | ||||
Widowed | 85 | 61 | 17 | 90 | 89 | 342 | ||||
Divorced | 47 | 90 | 156 | 25 | 102 | 420 | ||||
Total | 478 | 863 | 233 | 181 | 189 | 1944 | ||||
EXPECTED | ||||||||||
Abstain | 1-20 | 20-40 | 40-60 | Over 60 | FORMULA FOR EXPECTED VALUE | |||||
Single | 138.68 | 250.38 | 67.60 | 52.51 | 54.83 | =(B$7*$G3)/$G$7 | =(C$7*$G3)/$G$7 | =(D$7*$G3)/$G$7 | =(E$7*$G3)/$G$7 | |
Married | 339.32 | 612.62 | 165.40 | 128.49 | 134.17 | =(B$7*$G4)/$G$7 | =(C$7*$G4)/$G$7 | =(D$7*$G4)/$G$7 | =(E$7*$G4)/$G$7 | |
Widowed | 84.09 | 151.82 | 40.99 | 31.84 | 33.25 | =(B$7*$G5)/$G$7 | =(C$7*$G5)/$G$7 | =(D$7*$G5)/$G$7 | =(E$7*$G5)/$G$7 | |
Divorced | 103.27 | 186.45 | 50.34 | 39.10 | 40.83 | =(B$7*$G6)/$G$7 | =(C$7*$G6)/$G$7 | =(D$7*$G6)/$G$7 | =(E$7*$G6)/$G$7 | |
CHI-SQUARE | ||||||||||
Abstain | 1-20 | 20-40 | 40-60 | Over 60 | FORMULA FOR CHI-SQUARE | |||||
Single | 37.05 | 1.66 | 3.98 | 36.01 | 18.87 | =(B3-B11)^2/B11 | =(C3-C11)^2/C11 | =(D3-D11)^2/D11 | =(E3-E11)^2/E11 | |
Married | 15.14 | 0.68 | 1.63 | 14.72 | 7.71 | =(B4-B12)^2/B12 | =(C4-C12)^2/C12 | =(D4-D12)^2/D12 | =(E4-E12)^2/E12 | |
Widowed | 0.01 | 54.33 | 14.04 | 106.22 | 93.48 | =(B5-B13)^2/B13 | =(C5-C13)^2/C13 | =(D5-D13)^2/D13 | =(E5-E13)^2/E13 | |
Divorced | 30.66 | 49.89 | 221.78 | 5.09 | 91.63 | =(B6-B14)^2/B14 | =(C6-C14)^2/C14 | =(D6-D14)^2/D14 | =(E6-E14)^2/E14 | |
Test statistic | 804.57 | =SUM(B18:F21) | ||||||||
p-value | 0.000 | =CHISQ.TEST(B3:F6,B11:F14) |
H0: There is no association between marital status and alcohol consumption
H1: There is an association between marital status and alcohol consumption
Test statistic = 804.57
Degrees of freedom = (Rows-1)*(Columns-1) = (4-1)*(4-1) = 9
Level of significance = 0.05
p-value = 0.000
Since p-value is less than 0.05, we reject the null hypothesis.
So, there is an association between marital status and alcohol consumption.