Question

In: Statistics and Probability

Marital Status and Drinking Drinks per Month Marital Status Abstain            1-20     20-40          40-60   &nb

Marital Status and Drinking

Drinks per Month

Marital Status

Abstain            1-20    

20-40          40-60       over 60          

Single            

   67                 230    

    84               96              87

Married          

411                 633    

    149            85               102  

Widowed        

85                    61     

     17            90              89               

Divorced        

47                     90    

     25            102             156    

Perform a hypothesis to decide whether there is an association between marital status and alcohol consumption.

Solutions

Expert Solution

Solve using Excel in the following manner:

ACTUAL
Abstain 1-20 20-40 40-60 Over 60 Total
Single 67 230 84 96 87 564
Married 411 633 149 85 102 1380
Widowed 85 61 17 90 89 342
Divorced 47 90 156 25 102 420
Total 478 863 233 181 189 1944
EXPECTED
Abstain 1-20 20-40 40-60 Over 60 FORMULA FOR EXPECTED VALUE
Single 138.68 250.38 67.60 52.51 54.83 =(B$7*$G3)/$G$7 =(C$7*$G3)/$G$7 =(D$7*$G3)/$G$7 =(E$7*$G3)/$G$7
Married 339.32 612.62 165.40 128.49 134.17 =(B$7*$G4)/$G$7 =(C$7*$G4)/$G$7 =(D$7*$G4)/$G$7 =(E$7*$G4)/$G$7
Widowed 84.09 151.82 40.99 31.84 33.25 =(B$7*$G5)/$G$7 =(C$7*$G5)/$G$7 =(D$7*$G5)/$G$7 =(E$7*$G5)/$G$7
Divorced 103.27 186.45 50.34 39.10 40.83 =(B$7*$G6)/$G$7 =(C$7*$G6)/$G$7 =(D$7*$G6)/$G$7 =(E$7*$G6)/$G$7
CHI-SQUARE
Abstain 1-20 20-40 40-60 Over 60 FORMULA FOR CHI-SQUARE
Single 37.05 1.66 3.98 36.01 18.87 =(B3-B11)^2/B11 =(C3-C11)^2/C11 =(D3-D11)^2/D11 =(E3-E11)^2/E11
Married 15.14 0.68 1.63 14.72 7.71 =(B4-B12)^2/B12 =(C4-C12)^2/C12 =(D4-D12)^2/D12 =(E4-E12)^2/E12
Widowed 0.01 54.33 14.04 106.22 93.48 =(B5-B13)^2/B13 =(C5-C13)^2/C13 =(D5-D13)^2/D13 =(E5-E13)^2/E13
Divorced 30.66 49.89 221.78 5.09 91.63 =(B6-B14)^2/B14 =(C6-C14)^2/C14 =(D6-D14)^2/D14 =(E6-E14)^2/E14
Test statistic 804.57 =SUM(B18:F21)
p-value 0.000 =CHISQ.TEST(B3:F6,B11:F14)

H0: There is no association between marital status and alcohol consumption

H1: There is an association between marital status and alcohol consumption

Test statistic = 804.57

Degrees of freedom = (Rows-1)*(Columns-1) = (4-1)*(4-1) = 9

Level of significance = 0.05

p-value = 0.000

Since p-value is less than 0.05, we reject the null hypothesis.

So, there is an association between marital status and alcohol consumption.


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