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In: Statistics and Probability

A sample of 62 households was taken to measure the amount of discarded plastics. The sample...

A sample of 62 households was taken to measure the amount of discarded plastics. The sample mean was 1.911 lbs. and the standard deviation was 1.065 lbs. test the hypothesis test that the amount of discarded plastic per household was 1.8 lbs.

  1. State the null and alternative hypothesis (3 Points)
  1. Test Statistics (2 points)
  1. P-value approach ( 2 points)
  1. Conclusion: (3 points)   

Solutions

Expert Solution

Ho :   = 1.8 lbs
Ha :   1.8 lbs

Level of Significance (l.o.s.) : = 0.05 ( assuming this, since this is not given in the question.)

Test Statistics : One sample t-test ( since population variance is not known, we use Student's t-distribution)

Decision Criteria : Reject Ho at 5% l.o.s. if t cal > t tab,
where t tab = t ( /2 , n-1 ) = t(0.025 , 61) = 1.999624.

Calculation : = 1.911 lbs , s = 1.065 lbs and n = 62

t cal = =    = 0.82067124

Conclusion : Since t cal < t tab, we reject Ho at 5% l.o.s. and thus, conclude that the mean amount of discarded plastics is 1.8 lbs.

Hope this answers your query!

orchestra answered 1 year ago
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