In: Statistics and Probability
The average production cost for major movies is 59 million dollars and the standard deviation is 18 million dollars. Assume the production cost distribution is normal. Suppose that 40 randomly selected major movies are researched. Answer the following questions. Round all answers to 4 decimal places where possible.
Solution :
Given that ,
mean = = 59
standard deviation = =18
a) The distribution is approximately normal.
X ~ N ( 59,18)
b) The sampling distribution is approximately normal.
~ N (
n = 40
= = 59
= / n = 18 / 40 = 2.8460
P( 58< x < 61 ) = P[( 58 -59 )/18 ) < (x - ) / < (61-59 ) /18 ) ]
= P( -0.06 < z < 0.11 )
= P(z < 0.11) - P(z <-0.06 )
Using standard normal table
= 0.5438
Probability = 0.5438
c) P( 58 < < 61 )
= P[(58 -59) /2.8460< ( - ) / < (61 -59 ) / 2.8460 )]
= P( -0.35 < Z < 0.70)
= P(Z <0.70 ) - P(Z < -0.35)
= 0.758 - 0.3632 = 0.3948
probability =0.3948
d) Yes.