Question

In: Statistics and Probability

Note: You need to show your work. Be sure to upload your well-documented Excel and to...

Note: You need to show your work. Be sure to upload your well-documented Excel and to make note in this file how you arrived at your answers. If you choose to do the work by hand, Microsoft Word has an equation editor. Go to “Insert” and “Equation” on newer versions of Word. On older versions, go to “Insert” and “Object” and “Microsoft Equation.”

Player Round 1 Round 2
Michael Letzig 70 72
Scott Verplank 71 72
D.A. Points 70 75
Jerry Kelly 72 71
Soren Hansen 70 69
D.J. Trahan 67 67
Bubba Watson 71 67
Reteif Goosen 68 75
Jeff Klauk 67 73
Kenny Perry 70 69
Aron Price 72 72
Charles Howell 72 70
Jason Dufner 70 73
Mike Weir 70 77
Carl Pettersson 68 70
Bo Van Pelt 68 65
Ernie Els 71 70
Cameron Beckman 70 68
Nick Watney 69 68
Tommy Armour III 67 71

Chapter 10 (Excel file included):

Scores in the first and fourth (final) rounds for a sample of 20 golfers who competed in the PGA tournaments are included in the attached Excel file. Suppose you would like to determine if the mean score for the first round of a PGA Tour event is significantly different than the mean score for the fourth and final round. You are curious: Does the pressure of playing in the final round cause scores to go up? Or does the increased player concentration cause scores to come down?

  1. Use to test for a statistically significant difference between the populations means for the first- and fourth-round scores. What is the p-value? What is your conclusion?
  2. What is the point estimate for the difference between the two population means? For which round is the population mean score lower?
  3. Develop a 90% confidence interval estimate for the difference between the population means. Use the single population methodology where the confidence interval is given by . Notice that 0 is in this interval: what does this say about the statistical significance of the difference in the means?

Solutions

Expert Solution

H0: or the mean score for the first round of a PGA Tour event is not significantly different than the mean score for the fourth and final round

H1: or the mean score for the first round of a PGA Tour event is significantly different than the mean score for the fourth and final round.

1.We enter the values is excel as follows:

Player Round 1 Round 2
Michael Letzig 70 72
Scott Verplank 71 72
D.A. Points 70 75
Jerry Kelly 72 71
Soren Hansen 70 69
D.J. Trahan 67 67
Bubba Watson 71 67
Reteif Goosen 68 75
Jeff Klauk 67 73
Kenny Perry 70 69
Aron Price 72 72
Charles Howell 72 70
Jason Dufner 70 73
Mike Weir 70 77
Carl Pettersson 68 70
Bo Van Pelt 68 65
Ernie Els 71 70
Cameron Beckman 70 68
Nick Watney 69 68
Tommy Armour III 67 71

2.Then click on data--->dataanalysis---->t-test:two samples assuming equal variances.

The output is as follows for two tailed test:

t-Test: Two-Sample Assuming Equal Variances
Variable 1 Variable 2
Mean 69.65 70.7
Variance 2.765789474 9.168421053
Observations 20 20
Pooled Variance 5.967105263
Hypothesized Mean Difference 0
df 38
t Stat -1.359275376
P(T<=t) two-tail 0.182071918
t Critical two-tail 2.024394164

since, |t|=1.35927<tc=2.024394 we accept the null hypothesis hence,the mean score for the first round of a PGA Tour event is not significantly different than the mean score for the fourth and final round

2.p-value=0.1820719>0.05 hence we accept the null hypothesis.

3.A point estimate for the difference in two population means is simply the difference in the corresponding sample means.

hence,point estimate for difference of means=70.7-69.65=1.05

4.

90% confidence interval:

Player Round 1 Round 2 Difference
Michael Letzig 70 72 -2
Scott Verplank 71 72 -1
D.A. Points 70 75 -5
Jerry Kelly 72 71 1
Soren Hansen 70 69 1
D.J. Trahan 67 67 0
Bubba Watson 71 67 4
Reteif Goosen 68 75 -7
Jeff Klauk 67 73 -6
Kenny Perry 70 69 1
Aron Price 72 72 0
Charles Howell 72 70 2
Jason Dufner 70 73 -3
Mike Weir 70 77 -7
Carl Pettersson 68 70 -2
Bo Van Pelt 68 65 3
Ernie Els 71 70 1
Cameron Beckman 70 68 2
Nick Watney 69 68 1
Tommy Armour III 67 71 -4

for mean---->AVERAGE() function is used.

Mean= -1.05

for sample sd----->STDEV.S() function is used.

Sample sd= 3.316228041

for Margin of error---->CONFIDENCE.T() function is used.

Margin of error(E)= 1.282205813

lower limit=mean-E and upper limit=mean+E at 90% confidence interval:

Lower limit(mean-E) -2.33220581
Upper limit(mean+E) 0.232205813

please rate my answer and comment for doubts.


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