Question
In: Statistics and Probability
A survey found that women's heights are normally distributed with mean 62.5 in62.5 in. and standard...
A survey found that women's heights are normally distributed with mean
62.5 in62.5 in.
and standard deviation
2.5 in2.5 in.
The survey also found that men's heights are normally distributed with mean
68.4 in68.4 in.
and standard deviation
3.8 in3.8 in.
Consider an executive jet that seats six with a doorway height of
56.3 in56.3 in.
Complete parts (a) through (c) below.
a. What percentage of adult men can fit through the door without bending?
The percentage of men who can fit without bending is
nothing%.
Solutions
Expert Solution
Solution:
X: women's heights
µx = 62.5 in
σx = 2.5 in
Y : men's heights
µy = 68.4 in
σy = 3.8 in
The executive jet that seats six with a doorway height of 56.3 in
a. What percentage of adult men can fit through the door without bending?
P( y < 56.3) = P( (x-µy)/σy < ( (56.3-µy)/σy)
= P( z < -3.18 )
= 0.00074 (Using Table )
= 0.0007
The percentage of men who can fit without bending is 0.07 %.
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