Three dimensions. Three point particles are fixed in place in an xyz coordinate system. Particle A,...

Three dimensions. Three point particles are fixed in place in an xyz coordinate system. Particle A, at the origin, has mass m_A. Particle B, at xyz coordinates (3.00d, 2.00d, 4.00d), has mass 3.00m_A, and particle C, at coordinates (–3.00d, 3.00d, –2.00d), has mass 3.00m_A. A fourth particle D, with mass 3.00m_A, is to be placed near the other particles. If distance d = 9.90 m, at what (a) x, (b) y, and (c) z coordinate should D be placed so that the net gravitational force on A from B, C, and D is zero?

I need the answer in meters. Also, I already asked and someone ended up getting 0 for part a, -16.5 for part b and 22.9 for part c; none of those are correct. thanks

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genius_generous answered 1 year ago

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