Question

In: Statistics and Probability

Ten chickens, randomly selected, were treated weekly with a natural growth hormone. A certain quantity of...

Ten chickens, randomly selected, were treated weekly with a natural growth hormone. A certain quantity of the hormone (in grammes) was dissolved in 15 litres of drinking water. The weight of chickens were recorded after two weeks and the results are shown below.
feed cage #
A
B
C
D
E
F
G
H
I
J
K
L
M
Growth hormone (gm)
1
2
3
4
5
6
7
8
9
10
11
12
13
Weight (kg)
4.2
6.8
4.52
5.21
6.56
6.73
8.91
10.1
9.8
10.1
10.51
12.32
12.65
Answer the following questions
(i) State the strength of association between quantity of hormone and weight gain of chickens
(ii) What sort of effect does the hormone have on chicken weight?
(iii) What is the weight of the chicken a farmer would get without using any hormone?
(iv) The government recommends that the market weight of chickens should be between 6.5 and 9.0 kg. State the quantity of hormone that should be added to water.
(v) What will be the weight of chickens fed with 3.5g
(vi) How much hormone will a chicken weighing 10kg would have consumed?
(Use a 5% significance)

Solutions

Expert Solution

Suppose, random variables X and Y denote growth hormone (in gram) and weight (in kg) respectively.

(i)

Strength of association (Pearson's correlation coefficient) is given by

(ii)

We observe that correlation coefficient is highly positive (almost close to 1). Thus the hormone has a positive effect on chicken weight.

(iii)

We first obtain regression equation of Y on X as follows.

Regression equation of y on x is given by

Number of pairs of observation

In case of using no hormone,

Hence, 3.463077 kg weight of the chicken a farmer would get without using any hormone.

(iv)

We obtain regression equation of X on Y as follows.

Regression equation of x on y is given by

Number of pairs of observation

For ,

For ,

Hence, quantity of hormone to be added in water is 4.606911 gm to 7.859746 gm.

(v)

For ,

Hence, 5.901154 kg will be the weight of chickens that is fed with 3.5 g hormone.

(vi)

For ,

Hence, 9.16088 gm hormone a chicken weighing 10 kg should have consumed.


Related Solutions

Different hotels in a certain area are randomly​ selected, and their ratings and prices were obtained...
Different hotels in a certain area are randomly​ selected, and their ratings and prices were obtained online. Using​ technology, with x representing the ratings and y representing​ price, we find that the regression equation has a slope of 125 and a​ y-intercept of negative 374. Complete parts​ (a) and​ (b) below. a. What is the equation of the regression​ line? Select the correct choice below and fill in the answer boxes to complete your choice. A. yequals nothingplusleft parenthesis nothing...
The results for daily intakes of milk (in ounces) for ten randomly selected people were xˉ=18.23...
The results for daily intakes of milk (in ounces) for ten randomly selected people were xˉ=18.23 and s=6.11. Find a 99% confidence interval for the population standard deviation σ. Assume that the distribution of ounces of milk intake daily is normally distributed. What is the confidence interval? lower limit =Incorrect answer: 3.774 and the upper limit = Incorrect answer: 13.916
The daily intakes of milk (in ounces) for ten randomly selected people were: 26.0    13.0    13.5   ...
The daily intakes of milk (in ounces) for ten randomly selected people were: 26.0    13.0    13.5    14.8    19.1 13.6    21.6    30.8    15.8    14.1 Find a 99% confidence interval for the population variance. Assume that the distribution of ounces of milk intake daily is normally distributed. What is the confidence interval? lower limit =Incorrect answer: and the upper limit =Incorrect answer:
The daily intakes of milk (in ounces) for ten randomly selected children were: 23.3 28.4 10.5...
The daily intakes of milk (in ounces) for ten randomly selected children were: 23.3 28.4 10.5 16.4 26.4 18.1 20.4 17.3 27.4 13.2 Find a 98% confidence interval for the population mean μ.
Ten randomly selected mental institutions were examined to determine the effects of three different antipsychotic drugs...
Ten randomly selected mental institutions were examined to determine the effects of three different antipsychotic drugs on patients with the same type of symptoms. Each institution used one and only one of the three drugs exclusively for one year period. The proportion of treated patients in each institution who were discharged after one year of treatment were given below Drug1 0.1 0.12 0.08 0.14 Drug2 0.12 0.14 0.19 Drug3 0.2 0.25 0.15 a. Identify the outcome variable, factor, treatment, and...
Ten corvettes between 1 and 6 years old were randomly selected from the classified ads of...
Ten corvettes between 1 and 6 years old were randomly selected from the classified ads of The Arizona Republic. The following data were obtained, where x denotes age, in years, and y denotes price, in hundreds of dollars. X: 6 6 6 2 2 5 4 5 1 4 Y: 270 260 275 405 364 295 335 308 405 305 (A) Draw a scatter diagram (B) Find the Linear Correlation coefficient r. (C) Describe the shape, strength, and direction. (D)...
30 students were randomly selected from a large group of students taking a certain test. The...
30 students were randomly selected from a large group of students taking a certain test. The mean score for the students in the sample was 86. Assume that σ = 11.1. Construct a 99% confidence interval for the mean score, μ, of all students
Trade in Hormone-Treated Beef In the 1970s, scientists discovered how to synthesize certain hormones and use...
Trade in Hormone-Treated Beef In the 1970s, scientists discovered how to synthesize certain hormones and use them to accelerate the growth rate of livestock animals, reduce the fat content of meat, and increase milk production. Bovine somatotropin (BST), a growth hormone produced by cattle, was first synthesized by the biotechnology firm Genentech. Injections of BST could be used to supplement an animal’s own hormone production and increase its growth rate. These hormones soon became popular among farmers, who found that...
The following sample observations were randomly selected:
The following sample observations were randomly selected:12345X:213832Y:18132249            a. Not available in Connect.b. Determine the regression equation.(Negative answer should be indicated by a minus sign. Do not round intermediate calculations. Round the final answers to 4 decimal places.)                                           b =  a =Y' =  +  X           c. Determine the value of Y' whenX is 11. (Do not round intermediate calculations. Round the final answer to 4 decimal places.)
As part of a study of natural variation in blood chemistry, serum potassium concentrations were measured in 84 randomly selected healthy women
  As part of a study of natural variation in blood chemistry, serum potassium concentrations were measured in 84 randomly selected healthy women. The sample mean concentration was 4.36 mEq/l, and the sample standard deviation was 0.42 mEq/l. (a) Find the lower bound for the 95% confidence interval for the true serum potassium concentrate in healthy women. (b) Find the upper bound for the 95% confidence interval for the true serum potassium concentrate in healthy women. (c) Interpret your confidence...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT