In: Statistics and Probability
The US Poultry & Egg association claims that eating 2 eggs every morning for breakfast will increase (i.e. improve) your High-density lipoprotein (HDL) cholesterol levels. To test their claim, you conduct an experiment on 10 randomly chosen subjects. For 12 weeks they eat 2 eggs for breakfast every morning, after which you measure their HDL level. Then they eat just toast for breakfast every morning for 12 weeks after which you measure their HDL level. The results are in the table below. Based on this data, is there evidence that eggs increase your HDL level? Use a = 0.05.
Subject 1 2 3 4 5 6 7 8 9 10
HDL after eggs 60 63 70 75 55 50 62 56 71 48
HDL after toast 61 60 65 75 62 53 55 55 62 50
let d =after-Before |
null Hypothesis:μd | = | 0 | |
alternate Hypothesis: μd | > | 0 |
0.05 level with right tail test and n-1= 9 df, critical t= | 1.833 | from excel: 1*t.inv(0.05,9) | ||
Decision rule: reject Ho if test statistic t>1.833 |
S. No | after | Before | diff:(d)=x1-x2 | d2 |
1 | 60 | 61 | -1 | 1.00 |
2 | 63 | 60 | 3 | 9.00 |
3 | 70 | 65 | 5 | 25.00 |
4 | 75 | 75 | 0 | 0.00 |
5 | 55 | 62 | -7 | 49.00 |
6 | 50 | 53 | -3 | 9.00 |
7 | 62 | 55 | 7 | 49.00 |
8 | 56 | 55 | 1 | 1.00 |
9 | 71 | 62 | 9 | 81.00 |
10 | 48 | 50 | -2 | 4.00 |
total | = | Σd=12 | Σd2=228 | |
mean dbar= | d̅ = | 1.2000 | ||
degree of freedom =n-1 = | 9 | |||
Std deviaiton SD=√(Σd2-(Σd)2/n)/(n-1) = | 4.871687 | |||
std error=Se=SD/√n= | 1.5406 | |||
test statistic = | (d̅-μd)/Se = | 0.7789 | ||
p value | = | 0.2280 | from excel: tdist(0.779,9,1) |
since test statistic does not falls in rejection region we fail to reject null hypothesis |
we do not have have sufficient evidence to conclude that eggs increase your HDL level |