In: Physics
. A lorry with mass 3500 kg is parked at the top of a steep hill with a 1–in–8 gradient when its handbrake fails. Assume that the lorry has a constant frictional resistance to motion of 500 N. The lorry rolls 40 m down the hill before crashing into a lamp post. Use the principle of conservation of energy to calculate the velocity of the lorry immediately prior to its impact with the lamp post.
Answer:
Given data:
Mass of the lorry,
Resistive frictional force ,
Since the steep hill is 1-in-8 gradient, slope of the hill = ;
As the lorry travels 40 m before crashing, vertical descent =
Change in potential energy ,
While rolling, work done aganist frictional force,
By principle of Conservation of Energy,
As the lorry rolls down, the potential energy is get converted to kinetic energy.(Wfri energy is lossed to do work aganist frictional force)
i.e
i.e
velocity of the lorry immediately prior to its impact with the lamp post = 9.26 m/s