Question

In: Operations Management

LITTLE’S LAW: Diant grocery stores wish to estimate time customers spend, on average, in store and...

LITTLE’S LAW: Diant grocery stores wish to estimate time customers spend, on average, in store and in a checkout line. The results of the data collected are as below:

Avg. rate of customers entering store = 300 cust/hr

Avg. # of customers in store = 150 cust

% of customers who do not make a purchase = 5%

Avg. # customers in checkout lanes = 28.5 cust

a) How much time does the average customer spend in the store?

b) How much total time is spent, on average, to check out? Hint: This is the time that is spent in the checkout lane.

Solutions

Expert Solution

(a)

The time spent in the store is 0.50 hrs. = 30 minutes

(b)

The time spent in the checkout lane = 0.10 hrs. = 6 minutes

keosha answered 1 year ago
Next > < Previous

Related Solutions

Zingo's Grocery store claims that customers spend an average of 5 minutes waiting for service at...
Zingo's Grocery store claims that customers spend an average of 5 minutes waiting for service at the stores deli counter. A random sample of 45 customers was timed at the deli counter, and the average service time was found to be 5.75 minutes. Historically the standard deviation for waiting time is 1.75 minutes per customer.      a. Find the 95% confidence interval for the mean time that customers wait at the deli counter.      b. Is there sufficient evidence to...
Zingo's Grocery store claims that customers spend an average of 5 minutes waiting for service at...
Zingo's Grocery store claims that customers spend an average of 5 minutes waiting for service at the stores deli counter. A random sample of 45 customers was timed at the deli counter, and the average service time was found to be 5.75 minutes. Historically the standard deviation for waiting time is 1.75 minutes per customer.      a. Find the 95% confidence interval for the mean time that customers wait at the deli counter.      b. Is there sufficient evidence to...
Zingo's Grocery store claims that customers spend an average of 5 minutes waiting for service at...
Zingo's Grocery store claims that customers spend an average of 5 minutes waiting for service at the stores deli counter. A random sample of 45 customers was timed at the deli counter, and the average service time was found to be 5.75 minutes. Historically the standard deviation for waiting time is 1.75 minutes per customer. a. Find the 95% confidence interval for the mean time that customers wait at the deli counter. b. Is there sufficient evidence to indicate that...
A grocery store is interested in how much money, on average, their customers spend each visit in the produce department.
A grocery store is interested in how much money, on average, their customers spend each visit in the produce department. Using their store records, they draw a sample of 1,000 visits and calculate each customer’s average spending on produce. Who is the population of interest?
Customers arrive at a grocery store at an average of 2.2 per minute. Assume that the...
Customers arrive at a grocery store at an average of 2.2 per minute. Assume that the number of arrivals in a minute follows the Poisson distribution. Provide answers to the following to 3 decimal places. Part a) What is the probability that exactly two customers arrive in a minute? Part b) Find the probability that more than three customers arrive in a two-minute period. Part c) What is the probability that at least seven customers arrive in three minutes, given...
Customers arrive at a local grocery store at an average rate of 2 per minute. (a)...
Customers arrive at a local grocery store at an average rate of 2 per minute. (a) What is the chance that no customer will arrive at the store during a given two minute period? (b) Since it is a “Double Coupon” day at the store, approximately 70% of the customers coming to the store carry coupons. What is the probability that during a given two-minute period there are exactly four (4) customers with coupons and one (1) without coupons? (c)...
The manager of a grocery store has taken a random sample of 100 customers. The average...
The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 4.8 minutes with a sample standard deviation of 0.5 minutes. Conduct a test to determine whether or not the mean waiting time of all customers is significantly more than 5 minutes. Use a significance level of α = 0.01.
1. A grocery store counts the number of customers who arrive during an hour. The average...
1. A grocery store counts the number of customers who arrive during an hour. The average over a year is 29 customers per hour. Assume the arrival of customers follows a Poisson distribution. (It usually does.) Find the probability that at least one customer arrives in a particular one minute period. Round your answer to 3 decimals. Find the probability that at least two customers arrive in a particular 2 minute period. 2. Label each as one of the following...
(Operations Management) The grocery store gets an average of 50 customers per shift. The manager wants...
(Operations Management) The grocery store gets an average of 50 customers per shift. The manager wants to calculate whether he should hire one, two, three, or four salespeople. The average waiting times will be seven minutes with one salesperson, four minutes with two salespeople, three minutes with three salespeople, and two minutes with four salespeople. He has estimated the cost per minute that customers wait at $1. The cost per salesperson per shift (including fringe benefits) is $70. Analyze to...
The marketing director of a large department store wants to estimate the average number of customers...
The marketing director of a large department store wants to estimate the average number of customers who enter the store every five minutes. She randomly selects five-minute intervals and counts the number of arrivals at the store. She obtains the figures 56, 32, 41, 49, 56, 80, 42, 29, 32, and 70. The analyst assumes the number of arrivals is normally distributed. Using these data, the analyst computes a 95% confidence interval to estimate the mean value for all five-minute...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT