Question

1.) What is the positive control in this experiment? Negative control? Why do you think this?

Tube #	3 M Na Pyruvate(Activator)	0.1 M MgSO4 (activator)	0.1 M NaF (inhibitor)	5.0% Glucose (Activator)	Water	Fill With	Co2 Produced after 40 min
1	-	-	-	-	7.5 mL	Yeast	.10 mm
2	-	-	-	2.5 mL	5.0 mL	Yeast	2.5 mm
3	-	5.0 mL	-	2.5 mL	-	Yeast	5.0 mm
4	-	-	0.5 mL	2.5 mL	4.5 mL	Yeast	2.1 mm
5	-	-	5.0 mL	2.5 mL	-	Yeast	0.5 mm
6	2.5 mL	-	2.5 mL	2.5 mL	-	Yeast	4.3 mm
7	-	-	-	2.5 mL	2.5 mL	Water	0.0 mm

Answer 1

Positive control = 3

Negative control = 7

In the given experiment we are determine the amount of carbon dioxide produced after fomentation of pyruvic acid by yeast cells. Yeast cells are the source of enzymes.

A positive control is the one which will surely give us positive result. We use positive control in order to check that the enzyme is interacting with the specific substrate molecule. It is not interacting with another reagent present in the reaction medium. So maximum amount of carbon dioxide is liberated in third tube and this will be the positive control.

Negative control is the one which will not give us any result. In this to either the enzyme for substrate is absent. We use water instead. We use this type of control in order to ensure that there will be no reaction if anyone of the Agent of the experiment is absent in the reaction mixture. To the last tube tube number 7 will be the negative control because it is not liberating any amount of carbon dioxide.

Please give a good rating.