In: Statistics and Probability
A straight line is fitted to some data using least squares. Summary statistics are below. n=10, $\bar{x}=$5, $\bar{y}=$12, SSxx=142, SSxy=123, SSyy=155 The least squares intercept and slope are 7.65 and 0.87, respectively, and the ANOVA table is below.
Source | DF | SS | MS |
Regression | 1 | 106.54 | 106.54 |
Residual | 8 | 48.46 | 6.06 |
Total | 9 | 155 |
Compute a 95% confidence interval for the mean response when x=8.What is the critical value from the table? 2.3060 [1 pt(s)]
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Lower bound: Upper bound: [3 pt(s)]
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Compute a 95% prediction interval for a new observation when x=8
95% confidence interval :
predcited value at X=8 is 7.65+8*0.87= | 14.6100 | ||||
std error confidence interval= | s*√(1/n+(x0-x̅)2/Sxx) | = | 0.9950 | ||
for 95 % CI value of t= | 2.3060 | ||||
margin of error E=t*std error = | 2.2945 | ||||
lower confidence bound=sample mean-margin of error = | 12.3155 | ||||
Upper confidence bound=sample mean+margin of error= | 16.9045 |
95% prediction interval:
std error prediction interval= | s*√(1+1/n+(x0-x̅)2/Sxx) | = | 2.6552 | ||
for 95 % CI value of t= | 2.3060 | ||||
margin of error E=t*std error = | 6.12 | ||||
lower prediction bound=sample mean-margin of error = | 8.4871 | ||||
Upper prediction bound=sample mean+margin of error= | 20.7329 |