The Separation of Three Organic Compounds by Acid, Base Reactions and Liquid, Liquid Extraction.
Okay, so we had solid benzoic acid, ethyl 4- aminobenzoate, and 9-fluorenone all dissolved in diethyl ether. We separated the basic component by adding 3M HCl, we separated the acidic component by adding 3M NaOH. I don't understand what happens here. To isolate the acidic solution, we added 6 M NaOH and used the vacuum to recover the solid. To isolate the basic solution we added 6M HCl. I did an experiment where a 1:1:1 mixture of Benzoic Acid solid (C6H5COOH), ethyl 4-aminobenzoate solid (C9H11NO2), and 9-fluorenone solid (C13H8O) was dissolved with methylene chloride. Then each component was extracted and tested. I need to come up with a proton transfer chemical reaction that represents what happened in each separation. First separation: HCl was added and two layers formed. aqueous layer was extracted and transfer to a clean container and methylene chlotide layer was left aside. NaOH was added dropwise to aqueouse layer extraction and vacuum filtration was used to extract/separate the basic component ethyl 4-aminobenzoate solid (C9H11NO2).
Results &Data:
1)Benzoic acid (Acid)
Benzoic acid |
0.051g |
Tare dish |
0.419 g |
Dish with Solid (Benzoic acid) |
0.443 g |
Dry mass obtained (Final product after vacumming) |
0.441 g |
Melting point |
97.0 °C – 97.2 °C |
Table 1: Collected data from Benzoic acid
2) Benzoate (Base)
Benzoate |
0.050 g |
Tare dish |
0.406 g |
Dish with Solid (Benzoate) |
0.413 g |
Dry mass obtained (Final product after vacumming) |
0.408 g |
Melting point |
78.0 °C – 79.4 °C |
Table 2: Collected data from Benzoate.
3) 9-Fluorenone (Neutral)
9-Fluorenone |
0.050 g |
Tare tube |
11.360 g |
Dry mass obtained (Final product after drying) |
11.470 g |
Melting point |
89.4 °C – 89.5 °C |
Table 3: Collected data from 9-Fluorenone.
I need to find the theoretical and percent yield of each product, how many mg of each product is present. And also create 4 chemical reactions. Need help, Please help thankyou
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Calculate the change in standard-state entropy for the following reaction that results in the formation of glucose:
6 CO2(g) +6 H2O(l) ⟶ 1 C6H12O6(s) + 6 O2(g)
(If applicable, coefficients of one have been included for clarity.)
Express your answer with the appropriate units. Use FOUR significant figures.
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# |
[Myoglobin] (mg/mL) |
Myoglobin stock volume (mL) |
[GuHCl] (M) |
GuHCl stock volume (mL) |
Phosphate buffer volume (mL) |
Total volume (mL) |
1 |
0.2 |
0 |
1000 |
|||
2 |
0.2 |
0.4 |
1000 |
|||
3 |
0.2 |
0.8 |
1000 |
|||
4 |
0.2 |
1.0 |
1000 |
|||
5 |
0.2 |
1.2 |
1000 |
|||
6 |
0.2 |
1.3 |
1000 |
|||
7 |
0.2 |
1.4 |
1000 |
|||
8 |
0.2 |
1.5 |
1000 |
|||
9 |
0.2 |
1.6 |
1000 |
|||
10 |
0.2 |
1.7 |
1000 |
|||
11 |
0.2 |
1.8 |
1000 |
|||
12 |
0.2 |
2.0 |
1000 |
|||
13 |
0.2 |
2.2 |
1000 |
|||
14 |
0.2 |
2.6 |
1000 |
|||
15 |
0.2 |
3.0 |
1000 |
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. pH =
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