Within 100 g of pure benzene (C6H6) with freezing and boiling temperatures of 5.5 oC and...

Within 100 g of pure benzene (C6H6) with freezing and boiling temperatures of 5.5 oC and 80.1 oC respectively 24.4 g of biphenyl (C12H10) dissolves. Benzene freezing point lowering and boiling point rise constants 5.12 K kg mol-1 and 2.63 K kg mol-1 According to the solution at 80.1 oC Find the freezing and boiling temperatures of the solution as well as the vapor pressure. (Your normal gasoline steam pressure at boiling temperature of 80.1 oC p1 o = 760 mmHg.)

Solutions

Expert Solution

Solution:

Mass of solvent benzene, m = 100 g

Number of moles of biphenyl dissolved

= (mass of biphenyl)/(molar mass of biphenyl)

= (24.4 g)/(154.21g/mol)

= 0.158226 mol

Molality of the solution, m

= (moles of solute)/(mass of solvent)

= 1.58226 mol/kg

Amanda K answered 1 year ago

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