Members of the Beta Upsilon Tau fraternity each drink a random number of beers with mean...

Members of the Beta Upsilon Tau fraternity each drink a random number of beers with mean 6 and standard deviation 3.
If there are 81 fraternity members, how much should they buy so that using the normal approximation they are 93.32% sure they will not run out?

Expert Solution

µ =    6
σ =    3
n=   81
proportion=   0.9332

Z value at    0.9332   =   1.500   (excel formula =NORMSINV(   0.93   ) )
z=(x-µ)/(σ/√n)
so, X=z * σ/√n +µ=   1.500   *   3   / √    81   +   6   =   6.50

orchestra answered 2 years ago

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