Women have pulse rates that are normally distributed with a mean of 75.5 beats per minute...

Women have pulse rates that are normally distributed with a mean of 75.5 beats per minute and a standard deviation of 11.3 beats per minute.

a. Find the percentiles Upper P 1 and Upper P 99

P1= __________ beats per minute

Expert Solution

P(X < A) = P(Z < (A - mean)/standard deviation)

Mean = 75.5 beats per minute

Standard deviation = 11.3 beats per minute

a) P(X < P1) = 0.01

P(Z < (P1 - 75.5)/11.3) = 0.01

From standard normal distribution table,

(P1 - 75.5)/11.3 = -2.33

P1 = 49.17 beats per minute

P(X < P99) = 0.99

P(Z < (P99 - 75.5)/11.3) = 0.99

From standard normal distribution table,

(P99 - 75.5)/11.3 = 2.33

P99 = 101.83 beats per minute

orchestra answered 2 years ago

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