Question

In: Statistics and Probability

Assume the hold time of callers to a cable company is normally distributed with a mean...

Assume the hold time of callers to a cable company is normally distributed with a mean of 3.5 minutes and a standard deviation of 0.4 minutes. Determine the percent of callers who are on hold for more than 3.5 minutes. ​(Round to two decimal places as​ needed.)

Solutions

Expert Solution

Solution :

Given that,

mean = = 3.5

standard deviation = = 0.4

P(x > 3.5) = 1 - P(x< 3.5)

= 1 - P[(x -) / < (3.5- 3.5) /0.4 ]

= 1 - P(z < 0)

Using z table

= 1 - 0.50

=0.50

=50.00%

orchestra answered 2 years ago
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