In: Statistics and Probability
1. A candystore allows customers to select 3 different candies to be shipped. If there are a total of 10 varieties available, how many possible selections can be made?
2.The average cost of labor for car repairs for a chain of garages is $48.25. The standard deviation is $4.20. Assume normal distribution. If 20 stores are selected at random what is the probability that the mean of the sample labor cost will be between $46 and $48?
1) Using combination we can select 3 different candies from 10 varieties by,
Therefore, number of possible selection = 120
2) Given that, mean (μ) = $48.25 and
standard deviation = $4.20
sample size (n) = 20
We want to find,
Therefore, required probability is 0.3854