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he results of ANOVA test are summarized in Table 1. Table 1. Shows the results of...

he results of ANOVA test are summarized in Table 1.

Table 1. Shows the results of ANOVA for three different procedures

Source Sum of Square d.f Mean Square F
Between 160.13 80.97 9.17
Within (error) 104.80 8.73
Total 264.93 14


The degrees of freedom for between and within are:

Select one:

A. 1 and 13 respectively

B. 2 and 12 respectively

C. 3 and 11 respectively

D. 4 and 10 respectively

QUESTION 42

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A research group claims by taking a special vitamin, a weight lifter can increase his strength. After two weeks of training, supplemented with vitamin, they tested again. Test the effectiveness of the regiment at α = 0.05. Assume that the variable is normally distributed. The alternative hypothesis is :

Select one:

a. H0: µD ≥ 0

b. H0: µD = 0

c. H0: µD ≠ 0

d. H0: µD ≤ 0

QUESTION 43

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What is nP0? NEED TO FIND THEM N AND po

Select one:

A. 1

B. no answer

C. n

D. 0

QUESTION 44

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The data for a sample of 100 gave the regression line equation for age and blood pressure is Ÿ = 100 + 0.96X, and the standard error is 5. The 95% confidence interval of the prediction of the blood pressure of a person who is 43 years old showed that the lower confidence limit is :

Select one:

A. 125.67

B. 141.34

C. 142.34

D. 131.48

QUESTION 45

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A researcher wants to investigate if there is a difference in the rates of hotel room in two cities. A sample of 50 were selected from each city, the average hotel room in the first city is RM88.42 and in the second city is RM80.61 and the standard deviation are RM5.62 and RM4. The null hypothesis for the difference between the means is

Select one:

A. µ1 - µ2 ≤ 0

B. µ1 - µ2 = 0

C. µ1 - µ2 ≥ 0

D. µ1 - µ2 ≠ 0

QUESTION 46

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When a distribution is bell-shaped approximately what percentage of data values will fall within one standard deviation of the mean?

Select one:

A. 95%

B. 68%

C. 99.7%

D. 50%

QUESTION 47

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A repair team is responsible for a stretch of oil pipeline 2 miles long. The distance (in miles) at which any fracture occurs can be represented by a uniformly distributed random variable f(x) = 0.5

What is the probability that any given fracture occurs between 0.5 mile and 1.5 miles along this stretch pipeline?

Select one:

A. 0.2

B. 0.5

C. 0.1

D. 0.7

QUESTION 48

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In an advertisement, a retail store stated that its employees averaged nine years of service. The distribution is shown here.

Number of Employees   Years of Service
8 2
2 6
3 10

Using the weighted mean, the correct average is .........

Select one:

A. 4.5

B. 3.5

C. 5.4

D. 5.3

QUESTION 49

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The data for a sample of 100 gave the regression line equation for age and blood pressure is Ÿ = 100 + 0.96X, and the standard error is 5. The 95% confidence interval of the prediction of the blood pressure of a person who is 43 years old showed that the upper confidence limit is :

Select one:

A. 159.08

B. 149.09

C. 151.08

D. 155.08

QUESTION 50

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The variance for the data values “ 87, 85, 80, 78, 86, 90” is :

Select one:

A. 4.1

B. 12

C. 85

D. 17.1

Solutions

Expert Solution

Degree of freedom = sum of square / mean sum of square

DF between = 160.13 /80.97 = 1.97 which is equal to 2

DF within = 104.8 /8.73 = 12 which is equal to 12

So correct answer is option B 2 and 12 respectively

Answer 42:

As per the option whcih denotes the symbol of null hypothesis not the alternate hypothesis.

Null hypothesis should always shows equality and opposite to the business question so null hypothesis should stat that strenght will remain same or low after taking the vitamine and alternate hypothesis states that strength gets increased after taking vitamine

so correct answer based on the null hypothesis is option D: H0: ud ≤ 0

Answer 44:

Y =100+0.96 x

at x =43,

y = 100 +0.96*43

= 141.28 blood pressure

at 95 % confidence interval and 98 degree of freedom, it shows that t value is 1.9844

so standard error *1.9844 if we substract we will have lower bound

= 141.28 - 5*1.9844

= 131.48

So lower bound blood pressure at 95 % confidence interval of person having age 43 is 131.48 (Option D)

Answer 45:

The null hypothesis always shows the ]equality in the same so null hypothesis states that there is no price difference in the hotel room rent in both the cities.

SO correct opiton is B u1-u2 =0

Answer 46:

As per the emperical rule at 1 standard deviation on either side of mean will cover around 68 % of area so correct answer is option B 68%

Answer 48:

As per the formula of weighted average = sum of (year of experience * frequency of emplouee) / no. of employee

= 8*2+ 2*6+3*10/13

=58/13

=4.4615

So correct answer is option A 4.5

Answer 49:

Y =100+0.96 x

at x =43,

y = 100 +0.96*43

= 141.28 blood pressure

at 95 % confidence interval and 98 degree of freedom, it shows that t value is 1.9844

so standard error *1.9844 if we add we will have lower bound

= 141.28 + 5*1.9844

= 151.08

So upper bound blood pressure at 95 % confidence interval of person having age 43 is 151.08 (Option C)


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