In: Operations Management
A firm wants to decide on its production mix for two of its expensive products X and Y. The profit per unit of x is estimated to be LE 30,000, while the profit for unit of y is estimated to be LE10,000. Each unit of x requires 100 production hours while each unit of y requires 50 production hours and the firm has a total of 500 production hours available per week.
Q1) LP Model
Objective Function Maximize Profit Z = 30000X+10000Y
s.t. Constraints - 100X+50Y<=500 --> Production Hours constraint
X,Y>=0 --> Non-negativity constraint
Excel solution-
Maximum Profit = 150000 $ which produces 5 units of X and 0 units of Y
Solution | X | Y | ||
Decision variable | 5 | 0 | Maximize | |
Z | 30000 | 10000 | 150000 | |
Production Hours | 100 | 50 | 500 | 500 |
Solver with constraints
Q2) Additional constraint which produces atleast 4 units of Y
Objective Function Maximize Profit Z = 30000X+10000Y
s.t. Constraints - 100X+50Y<=500 --> Production Hours constraint
Y>=4 --> Units constraint for Y
X,Y>=0 --> Non-negativity constraint
Excel solution-
Maximum Profit = 130000 $ which produces 3 units of X and 4 units of Y
Solution | X | Y | ||
Decision variable | 3 | 4 | Maximize | |
Z | 30000 | 10000 | 130000 | |
Production Hours | 100 | 50 | 500 | 500 |
Y units | 0 | 1 | 4 | 4 |
Solver with constraints -
Q3) Additional constraint which produces atmost 2 units of X
Excel Solution-
Maximum Profit = 120000 $ which produces 2 units of X and 6 units of Y
Solution | X | Y | ||
Decision variable | 2 | 6 | Maximize | |
Z | 30000 | 10000 | 120000 | |
Production Hours | 100 | 50 | 500 | 500 |
X units | 1 | 0 | 2 | 2 |
Solver with constraints -
Q4) Additional constraints where X<=2 and Y>=4
Maximum Profit = 120000 $ which produces 2 units of X and 6 units of Y
Excel Solution -
Solution | X | Y | ||
Decision variable | 2 | 6 | Maximize | |
Z | 30000 | 10000 | 120000 | |
Production Hours | 100 | 50 | 500 | 500 |
X units | 1 | 0 | 2 | 2 |
Y units | 0 | 1 | 6 | 4 |
Solver with constraints -