Question

In: Chemistry

1)Let’s say that you recovered 80% trimyristin (after recrystallization, so the final product) from the 2...

1)Let’s say that you recovered 80% trimyristin (after recrystallization, so the final product) from the 2 g of nutmeg you initially started with.

a- If you completed the hydrolysis reaction (see lab) to make myristic acid and glycerol, what would be your theoretical yield of myristic acid?

b- If you recovered 1.72 g of myristic acid, what would be your percent recovery of myristic acid?

c- What might account for sources of error in your recovery?(Give 3 plausible reasons)

Solutions

Expert Solution

a- If you completed the hydrolysis reaction (see lab) to make myristic acid and glycerol, what would be your theoretical yield of myristic acid?

Given that; recovered 80% trimyristin

The initially amount of nutmeg = 2 g

2.0 g/ 80%= 1.6 g

Now calculate the moles of trimytrisin

= amount in g / molar mass

= 1.6 g/723.14 g/ mole

= 2.21*10^-3 moles

1 mole of trimytrisin given 3 mole myristic

2.21*10^-3 moles trimytrisin * 3 mole myristic/1 mole of trimytrisin

= 6.64*10^3mole myristic

Amount of myristic = molar mass * number of moles

= 6.64 *10^3mole myristic * 228.37 g

= 1.52 g

b- If you recovered 1.72 g of myristic acid, what would be your percent recovery of myristic acid?

% recovery = actual recovery / theoretical recovery *100

=1.72 g/ 2.00 g*100

= 86%

c- What might account for sources of error in your recovery?(Give 3 plausible reasons)

  1. Due to overheating the nutmeg dichloromethane mixtures decompose.
  2. May be less of accuracy in recovering.
  3. In pouring the liquid over celite pad

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