What would be the value of the mean for a binomial distribution that 141 trials and...

What would be the value of the mean for a binomial distribution that 141 trials and a success probability of 0.19?

What would be the value of the mean for a binomial distribution that 186 trials and a success probability of 0.68?

What would be the value of the mean for a binomial distribution that 80 trials and a success probability of 0.49?

What would be the value of the mean for a binoial distribution that 175 trials and a success probability of 0.09?

Solutions

Expert Solution

solution

Using binomial distribution,

mean and standard deviation

(A)Mean = = n * p = 141* 0.19= 26.79

Mean = =26.79

(B)

Mean = = n * p = 186* 0.68= 126.48

Mean = =126.48

(C)

Mean = = n * p = 80* 0.49= 39.2

Mean = =39.2

(D)

Mean = = n * p = 175* 0.09= 15.75

Mean = =15.75

orchestra answered 1 year ago

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