Question

Question

Use the data in the following​ table, which lists​ drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the table. ​

Drive-thru Restaurant  /  A  /  B  /  C  /  D
Order Accurate         / 20 / 42 / 43 / 21
Order Not Accurate     / 39 / 26 / 45 / 31

If one order is​ selected, find the probability of getting an accurate order given the order is from Restaurant A. Express your answer as a percentage rounded to the nearest hundredth.

Question

Use the data in the following​ table, which lists​ drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the table. ​

Drive-thru Restaurant  /  A  /  B  /  C  /  D
Order Accurate         / 24 / 19 / 58 / 44
Order Not Accurate     / 5 / 10 / 9 / 14

If three different orders are​ selected, find the probability that they are all from restaurant B. Assume that the orders are selected with replacement. Express your answer as a percentage rounded to the nearest hundredth.

Answer 1

Part 1

The table is as follows

	A	B	C	D	Total
Accurate	20	42	43	21	126
Not Accurate	39	26	45	31	141
Total	59	68	88	52	267

We need to find If one order is​ selected, the probability of getting an accurate order given the order is from Restaurant A

P(accurate order/order is from A) = Number of accurate orders from A / Number of total orders from A

= 20/59 = 0.34

So, the answer is 34%

Part 2

Setting the table

	A	B	C	D	Total
Accurate	24	19	58	44	145
Not Accurate	5	10	9	14	38
Total	29	29	67	58	183

Since the orders are selected with replacement, the three events would be independent, not affecting the probability of each. They will have the same probability

Probability of selecting an order from B = No. of order from B/ Total orders

= 29/183

the probability that all three are from restaurant B = (29/183) * (29/183) * (29/183) = 0.00398

So, the answer is 0.4%