Find the minimum energy for a neutron in a uranium nucleus whose diameter is 15fm.

Solutions

Expert Solution

Calculation new energy of neutrons:

Δx Δp ≥ ℏ/2

⇒ Δp ≥ . ℏ/2Δx

K.E = ρ2/2m ≤ (ℏ/2Δx) = 1/2m

K.Emin = 1/2mc2(ℏc/2Δx)2

K.Emin = (197 MeV/2 × 15){1/2 × (940 MeV)}

K.Emin = 23 keV

Conclusion:

The minimum energy of neutron is "23 keV".

Junaid answered 2 years ago

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