In: Statistics and Probability
Rim is not a good student. Her exam strategy is to rely on luck for the next exam. The exam consists of 20 questions. Each question has 5 possible answers, only one of which is correct. Rim plans to guess the answer to each question. Answer the following questions:
Problem 2:
2. You are given different scenarios for the rates of returns for Intek and Zurick stocks.
Scenario |
Probability |
Return (Intek) |
Return (Zurick) |
Boom |
0.35 |
12% |
6% |
Normal |
0.25 |
2% |
4% |
Recession |
0.4 |
-4% |
-1% |
Binomial distribution
the number of wrong Now, The probability Ket x be the random variable denoting the number of connect answers and Y be the nandom vaniable denoting answers. X follows binomial distribution with success probability 1/5 and Y ~ binomial distribution with success proobability 4. mass functions are given by! P(x-x) - ( 2 ) (0.23% (0.8)2 P (NY)= ( 20 ) (0.87% (0.2) 20-y. a) Required probability: PCY=6) ( 23 ) (0.8)0(012)44 = 166 10-6 b) Requined probability: P(x>5) = 1- P(xL5) { P(X-0) +P (x+1)+...+ = 1 - (0.0L * 0.06 +0:14 +0.20 +0.22) 20 -2 2 21- P (x=4)} a 1 - 0.63 - 0.37 Ans
We know that, E(x) = np 20x 0.2 = 4 : Expected value of the number of correct answers is 4 Nar (Y) = npq = nb. (1.b) = 200.8x0.2 = 32 standard deviation (4) - (3.278.5 - 1.79 The standard deviation of the number of wrong numbers as 1.79. Ang is given