In: Physics
Calculate the length of the de broglie wave of an electron and a proton moving with a kinetic energy of 1keV. For what values of kinetic energy will their wavelength be equal to 0.1 nm? me = 9.1.10 31kg, e = 1.602.10-19C, mp = 1.627.10-27 kg
the answers are,
De broglie wavelength of electron = 38.8 ×10-12m
De broflie wavelength of proton = 91.8 × 10-14 m
Kinetic energy of electron = 150.6 eV
Kinetic energy of proton = 0.084 eV.