In: Accounting
Harris County is planning to construct a Dam some tens of miles away from the Houston Metropolis Recreation center to facilitate Power Generation and fishing in the El Santos River Basin. The first cost for the Dam will amount to $7,500,000. Annual maintenance and repairs will amount to $25,000 for the first six years, to $30,000 for each year in the next eight years, and to $35,000 per year for the next six years. At the end of the 20th year, $24,000 is estimated to be deposited into Harris county account as tax credits earned for its environmental compliance in the construction and operation of the Dam. In addition a major overhaul costing $550,000 will be required at the end of the seventh year. Use an interest rate of 10% and :
Determine the engineering economy symbols and their corresponding values.
Construct the cash flow diagram
Calculate the Capital Recovery for the project
Determine the total Annual Worth for the Project
What is the Present worth of this project
Cost is indicated as positive value and tax credit as negative value.
Cash flow diagram is as follows: All values are in '000
Cash Inflow | 7500 25 25 25 25 25 25 580 30 30 30 30 30 30 30 35 35 35 35 35 24 | |||||||||||||||||||||
Period | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | |||||||||||||||||||||
Cash Outflow | 7500 25 25 25 25 25 25 580 30 30 30 30 30 30 30 35 35 35 35 35 35 |
Capital Recovery Factor for the initial capital investment of 7.5 Million $ @ 10% Interest Rate
= 7,500,000 *{(0.1*(1+0.1)^20)/((1+0.1)^20)-1}
= 7,500,000 *0.11746
= 880,947.2 $
Year | Description | Amount | PV Factor | PV Amount |
0 | Initial Investment | 7,500,000 | 1.0000 | 7,500,000 |
1 | Annual Maintenance & Repairs-1 | 25,000 | 0.9091 | 22,727 |
2 | Annual Maintenance & Repairs-1 | 25,000 | 0.8264 | 20,661 |
3 | Annual Maintenance & Repairs-1 | 25,000 | 0.7513 | 18,783 |
4 | Annual Maintenance & Repairs-1 | 25,000 | 0.6830 | 17,075 |
5 | Annual Maintenance & Repairs-1 | 25,000 | 0.6209 | 15,523 |
6 | Annual Maintenance & Repairs-1 | 25,000 | 0.5645 | 14,112 |
7 | Annual Maintenance & Repairs-2 | 30,000 | 0.5132 | 15,395 |
7 | Major Overhaul Costing | 550,000 | 0.5132 | 282,237 |
8 | Annual Maintenance & Repairs-2 | 30,000 | 0.4665 | 13,995 |
9 | Annual Maintenance & Repairs-2 | 30,000 | 0.4241 | 12,723 |
10 | Annual Maintenance & Repairs-2 | 30,000 | 0.3855 | 11,566 |
11 | Annual Maintenance & Repairs-2 | 30,000 | 0.3505 | 10,515 |
12 | Annual Maintenance & Repairs-2 | 30,000 | 0.3186 | 9,559 |
13 | Annual Maintenance & Repairs-2 | 30,000 | 0.2897 | 8,690 |
14 | Annual Maintenance & Repairs-2 | 30,000 | 0.2633 | 7,900 |
15 | Annual Maintenance & Repairs-3 | 35,000 | 0.2394 | 8,379 |
16 | Annual Maintenance & Repairs-3 | 35,000 | 0.2176 | 7,617 |
17 | Annual Maintenance & Repairs-3 | 35,000 | 0.1978 | 6,925 |
18 | Annual Maintenance & Repairs-3 | 35,000 | 0.1799 | 6,295 |
19 | Annual Maintenance & Repairs-3 | 35,000 | 0.1635 | 5,723 |
20 | Annual Maintenance & Repairs-3 | 35,000 | 0.1486 | 5,203 |
20 | Tax Credit Earned | (24,000) | 0.1486 | (3,567) |
Present Value Worth of Project | 8,018,035 |
Present Value Worth of Project = 8,018,035 $
Average Annual Worth of Project = 8,018,035 *{(0.1*(1+0.1)^20)/((1+0.1)^20)-1}
= 941,795.3 $