In: Biology
Part A - Carbon atoms in acetyl CoA formation and the citric acid cycle
During acetyl CoA formation and the citric acid cycle, all of the carbon atoms that enter cellular respiration in the glucose molecule are released in the form of CO2. Use this diagram to track the carbon-containing compounds that play a role in these two stages.
Drag the labels from the left (which represent numbers of carbon atoms) onto the diagram to identify the number of carbon atoms in each intermediate in acetyl CoA formation and the citric acid cycle. Labels may be used more than once.
Part B - Net redox reaction in acetyl CoA formation and the citric acid cycle
In the sequential reactions of acetyl CoA formation and the citric acid cycle, pyruvate (the output from glycolysis) is completely oxidized, and the electrons produced from this oxidation are passed on to two types of electron acceptors.
Drag the labels on the left to show the net redox reaction in acetyl CoA formation and the citric acid cycle. Note that two types of electron carriers are involved.
Part C - Why is the citric acid cycle a cyclic pathway rather than a linear pathway?
In the oxidation of pyruvate to acetyl CoA, one carbon atom is released as \(\mathrm{CO}_{2}\). However, the oxidation of the remaining two carbon atoms-in acetate- -to \(\mathrm{CO}_{2}\), requires a complex, eight-step pathway-the citric acid cycle. Consider four possible explanations for why the last two carbons in acetate are converted to \(\mathrm{CO}_{2}\) in a complex cyclic pathway rather than through a simple, linear reaction.
Answer A:
a. Acetyl CoA -2C
b. Citrate -6C
c. Isocitrate -6C
d. alpha-ketoglutarate -5C
e. Succinyl CoA -4 C
f. Succinate -4C
g. Fumarate -4C
h. Malate -4C
i. Oxaloacetate -4C
Answer B:
a. \(\mathrm{CO}_{2}\)
b. NADH
C. FAD
d. FADH \(_{2}\)
Answer C:
Option \(\mathrm{b}\) - It is easier to remove electrons and produce \(\mathrm{CO}_{2}\) from compounds with three or more carbon atoms than from a two-carbon compound such as acetyl CoA.
Acetyl CoA can be also be directly oxidized to two molecules of \(\mathrm{CO}_{2}\), however, energetically, it is more economical for the cell to add acetyl CoA to citrate and then oxidize it.