Question

In: Statistics and Probability

In 1983, the General Social Survey asked the question, “Do you think a woman should be...

In 1983, the General Social Survey asked the question, “Do you think a woman should
be able to have an abortion for any reason?” Of the 1515 people asked, 539 said yes; the
rest said no. In 1999, the General Social Survey asked 877 people the same question,
and 361 responded yes; the rest said no. Denote the true proportion of people who felt
that women should be able to have an abortion for any reason in 1983 by p1, and the
proportion in 1999 by p2.
(a) Is there sufficient evidence indicating the proportion of people who felt
that women should be able to have an abortion for any reason increased from 1983
to 1999? Specify the hypothesis, find rejection region at α level and p-value. (Hint:
use pooled sample proportion.)
(b) Argue that the conclusion at α level are equivalent using rejection region and p-value.

Solutions

Expert Solution

The null and alternative hypothesis is as

Ho : There is no sufficient evidence that indicating the proportion of people who felt
that women should be able to have an abortion for any reason increased from 1983
to 1999

H1 : There is sufficient evidence that indicating the proportion of people who felt
that women should be able to have an abortion for any reason increased from 1983
to 1999

Using notation the null and alternative hypothesis is as

Ho : P1 = P2

H1 : P1 < P2

Here P1 & P2 true proportion of 1983 and 1999 respectively

The values provided in the above question are as follows

For computational simplicity we use the notation is as follows

In 1983

X1 = 539

n1 = 1515

In 1999

X2 =361

n2 = 877

1) p1 = sample proportion in 1983

p1 = X1/n1 = 539/1515 = 0.3558

2) p2 = sample proportion in 1999

p2 = X2/n2 = 361/877 = 0.4116

We using the formula of test statistic for used pooled sample proportion is

pooled sample proportion is calculate using following formula

Using all above values in the following formula

Here test statistic Z = -2.7087-----------(1)

Here level of significance α is not given so, we used α = 0.05

Critical value of Z at α = 0.05 = -1.6449---------(2)

We find P value of test statistic using following command in Excel and then press Enter

=NORMSDIST(Z) then press Enter here, =NORMSDIST(-2.7087) = 0.0034

P value = 0.0034

By using P value we decide the null hypothesis is accept or reject by using following condition

1) P value   then we reject Ho

2)  P value   then we accept Ho

In this problem P value = 0.0034 and = 0.05

P value = 0.0034 = 0.05 We reject Ho.

There is sufficient evidence that indicating the proportion of people who felt
that women should be able to have an abortion for any reason increased from 1983
to 1999


Related Solutions

The General Social Survey asked 1,578 US residents: “Do you think the use of marijuana should...
The General Social Survey asked 1,578 US residents: “Do you think the use of marijuana should be made legal, or not?” 61% of the respondents said it should be made legal. Construct a 95% confidence interval for the proportion of US residents who think marijuana should be made legal (p), and interpret it in the context of the data.
General Social Survey asked participants if they thought it was “OK” for a woman to get...
General Social Survey asked participants if they thought it was “OK” for a woman to get an abortion for any reason and also asked them for their political party affiliation. The table below summarizes the data. Yes, “Ok” No, Opposed Strong Democrat 145 123 Independent 128 282 Strong Republican 46 162 Consider the following two events: A = the event a person is a Strong Republican, B = the event a person is ok to a woman getting an abortion...
The 2010 General Social Survey asked 1,259 US residents: "Do you think the use of marijuana...
The 2010 General Social Survey asked 1,259 US residents: "Do you think the use of marijuana should be made legal, or not?" 48% of the respondents said it should be made legal. 1. The value 48% is a... A. sample statistic B. population parameter 2. Construct a 95% confidence interval for the proportion of US residents who think marijuana should be made legal, and interpret it in the context of the data. Round your results to 3 decimal places. (...
A survey of 300 hospital workers is taken. The question asked is "Do you think that...
A survey of 300 hospital workers is taken. The question asked is "Do you think that staffing is adequate at your hospital, yes or no?" Perform the Chi-square test to determine if the frequency of no responses is statistically larger than the frequency of yes responses. The following responses were received: yes - 120, no - 180.
In the 2008 General Social Survey, participants were asked: “To what extent do you consider yourself...
In the 2008 General Social Survey, participants were asked: “To what extent do you consider yourself a religious person?” Of 2023 surveyed, 317 responded: “not at all.” (a) Construct a 95% confidence interval for the true proportion of US adults who would respond “not at all” to this question. (b) What is the margin of error for your confidence interval? (c) How large would the sample need to be to obtain a margin of error of ±1%?
Are you an optimist? The General Social Survey asked 1373 men and 993 women in the...
Are you an optimist? The General Social Survey asked 1373 men and 993 women in the United States whether they agreed that they were generally optimistic about the future. The results are presented in the flowing table. Male Female Optimistic 1148 815 Pessimistic 225 178 Compute the value of the chi square statistics. Can you conclude that the gender and the option on optimism are independent? using the α=0.05 level of significance Type Artificial hips: Artificial hip joints consist of...
The 2010 General Social Survey asked the question: “For how many days during the past 30...
The 2010 General Social Survey asked the question: “For how many days during the past 30 days was your mental health, which includes stress, depression, and problems with emotions, not good?” Based on responses from 1,151 US residents, the survey reported a 95% confidence interval of 3.40 to 4.24 days in 2010. (a) Interpret this interval in the context of the data. (b) What does “95% confidence” mean? Explain in the context of the application. (c) Suppose the researchers think...
The 2010 General Social Survey asked the question: "For how many days during the past 30...
The 2010 General Social Survey asked the question: "For how many days during the past 30 days was your mental health, which includes stress, depression, and problems with emotions, not good?" Based on responses from 1,151 US residents, the survey reported a 95% confidence interval of 3.40 to 4.24 days in 2010. (a) Interpret this interval in context of the data. 95% of surveys will report a mean number of ''not good'' days in the past 30 is between 3.40...
Relaxing after work. The 2010 General Social Survey asked the question: "After an average work day,...
Relaxing after work. The 2010 General Social Survey asked the question: "After an average work day, about how many hours do you have to relax or pursue activities that you enjoy?" to a random sample of 1130 Americans. A 93% confidence interval for the mean number of hours spent relaxing or pursuing activities they enjoy was [1.16, 1.84]. (a) Interpret this interval in context of the data: "There is a 93% chance that the average number of hours spent by...
In a General Social Survey on women’s role and in response to the question, "It is...
In a General Social Survey on women’s role and in response to the question, "It is much better for everyone involved if the man is the achiever outside the home and the woman takes care of the home and family." Of 411 male respondents, 153 (37.2%) replied yes. Of 472 female respondents, 166 (35.2%) replied yes. (a) Set up notation and specify hypotheses for the hypothesis of no difference between the population proportions of males and of females who would...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT