In: Math
The area of a particular rectangle is 12 times the area of a certain square, and the width of the rectangle is three times the length of a side of the square. The perimeter of the rectangle is 30 units greater than the perimeter of the square. Find the dimensiuons of both the rectangle and the square.
here, width of the rectangle is three times the length of a side of the square so,
let represent the width of the rectangle, then represents the length of the side of the square
the perimeter of the rectangle is 30 units greater than the perimeter of the square:
perimeter of the square:
perimeter of the rectangle is then
the area of the rectangle is 12 times the are of the square:
area of the square:
area of the rectangle:
let 'L' represent the length of the rectangle, then for perimeter and area of the rectangle we have,
or
substituting with :
but here
so,
the rectangle has dimensions 9x12
but represents the length of the side of the square
so
the square has dimensions 3x3