Find the first 6 terms of the Taylor Series for ln (x) around 1,
that is x = c = 1. Then use your results to calculate ln (3.52) and
get the absolute error.
I'm supposed to find the first 6 terms of the Taylor series
for the functions ln (x ) centered at 1 that is x = c = 1.( or
a=1). Then use the results to calculate ln (3.52) and get the
absolute error.
Use the definition of Taylor series to find the first three
nonzero terms of the Taylor series (centered at c) for the
function f.
f(x) = 7 tan x, c = 9π
use the definition of the Taylor series to find the first four
nonzero terms of the series for f(x) centered at x = a
a) f(x) = xe^x, a = 0
b) f(x) = sin (x), a = π/6
7. Determine
the first 4 nonzero terms of the Taylor series for the solution
y = φ(x) of the given initial value
problem, y’’ +
cos(x)y’ +
x2y = 0; y(0) = 1,
y’(0) = 1.
What do you expect the radius of convergence to be? Why?
please show all steps
Find the Taylor series or polynomial generated by the following
functions
a. )f(x) √ x centred at x=4 , of order 3
b.) f(x) cosh x= e^x+e^-x/(2), centred at x=0
c.) f(x) = x tan^-1x^2 , centred at x=0
d.) f(x) = 1/(√1+x^3) , centred at x=0 , of order 4
e.) f(x) = cos(2x+pie/2) centred at x= pie/4
1. If f(x) = ln(x/4)
-(a) Compute Taylor series for f at c = 4
-(b) Use Taylor series truncated after n-th term to compute f(8/3)
for n = 1,.....5
-(c) Compare the values from above with the values of f(8/3) and
plot the errors as a function of n
-(d) Show that Taylor series for f(x) = ln(x/4) at c = 4 represents
the function f for x element [4,5]