In: Accounting
Today (year 0) a new 7-megaWatt (MW) solar panel farm is
constructed at a cost of MYR14 million. 4 years from today, a
smaller 6-MW solar farm will be added to the existing farm. The
inflation rate on solar panel construction projects averages 8% per
year. If the cost-capacity factor is 0.85 for solar panel
construction, what is the estimated capital investment for the
smaller 6-MW solar farm?
ANSWER:
Given that
Solar panel farm = 7megawatt
Cost = MYR14million
Time =4yrs
Project average=8%per yr
Cost capacity factor=0.85
Estimated capital investment=6MW
We know that,
initially of completely the fee has to be escalated for "Four
living from today" inflation rate:
Per MW expenditure in our day = $14 million/7 $2 million
Per MW asking price "Four existence from today" = 2*(1+0.08)^4=$ 2.72097792 million
So expense of6 MW lodge "Four living from today" must be 6 *$ 2.72097792
million= $ 16.32586752 million
Now applying the expense factoring formula as apiece the formula beloW..
SB/SA = (Capp/Capa)^e
(equation 1)
where SA and SB are the expenses of the two akin projects,
Capa
and Capg are the capacities of the two projects, and "e is
the
exponent (or post factor) that drives the non-linear
relation-
ship
$B $16.326 M * (6/7)085 = $16.326 *0.877193144
=$ 14.03509031Million~
Then finally we got the ans
Hence the estimated headquarters investment for the less important 6-MW solar farm
=$14.035 Million
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