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A rotating wheel requires 2.97-s to rotate through 37.0 revolutions. Its angular speed at the end...

A rotating wheel requires 2.97-s to rotate through 37.0 revolutions. Its angular speed at the end of the 2.97-s interval is 97.0 rad/s. What is the constant angular acceleration of the wheel? _____ rad/s2

Solutions

Expert Solution

Time period = T = 2.97 sec

Number of revolutions = n = 37 rev

Angle through which the wheel rotated =

= 2n

= 2(37)

= 232.478 rad

Initial angular speed of the wheel = 1

Final angular speed of the wheel = 2 = 97 rad/s

Angular acceleration of the wheel =

2 = 1 + T

1 = 2 - T

= 1T + T2/2

= (2 - T)T + T2/2

= 2T - T2 + T2/2

= 2T - T2/2

232.478 = (97)(2.97) - (2.97)2/2

= 12.61 rad/s2

Constant angular acceleration of the wheel = 12.61 rad/s2

genius_generous answered 2 years ago
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