In: Statistics and Probability
A bank that offers charge cards to customers studies the yearly purchase amount (in thousands of dollars) on the card as related to the age, income (in thousands of dollars), and the and years of education of the cardholder. Using the Excel printout answer the following questions.
SUMMARY OUTPUT |
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Regression Statistics |
||||
Multiple R |
0.9629 |
|||
R Square |
_ _ _ _ |
|||
Adjusted R Square |
0.9144 |
|||
Standard Error |
0.0871 |
|||
Observations |
21.0000 |
|||
ANOVA |
||||
df |
SS |
MS |
F |
|
Regression |
- - - |
- - - - - - |
- - - - - |
- - - - - |
Residual |
- - - |
0.1290 |
- - - - - |
|
Total |
20 |
1.7737 |
||
Coefficients |
Standard Error |
t Stat |
P-value |
|
Intercept |
-0.8880 |
0.2604 |
-3.4108 |
0.0033 |
Age |
- - - - |
0.0094 |
3.7191 |
0.0017 |
Income |
0.0116 |
0.0156 |
0.7454 |
0.4662 |
Education |
0.0075 |
0.0082 |
- - - - - |
0.3768 |
a) R square = 0.9629^2 = 0.927176
df regression= number of independent variable = 3
df residual = 20-3 = 17
SSR = SST-SSE = 1.6447
MSR =SSR/df regression = 0.548233
MSE = SSE/df residual = 0.007588
F = MSR/MSE = 72.2478
Coefficient of age = t*Standard error = 0.03496
T for Education = Coeff/SE = 0.914634
Regression Statistics | ||||
Multiple R | 0.9629 | |||
R Square | 0.927176 | |||
Adjusted R Square | 0.9144 | |||
Standard Error | 0.0871 | |||
Observations | 21 | |||
ANOVA | ||||
df | SS | MS | F | |
Regression | 3 | 1.6447 | 0.548233 | 72.2478 |
Residual | 17 | 0.129 | 0.007588 | |
Total | 20 | 1.7737 | ||
Coefficients | Standard Error | t Stat | P-value | |
Intercept | -0.888 | 0.2604 | -3.4108 | 0.0033 |
Age | 0.03496 | 0.0094 | 3.7191 | 0.0017 |
Income | 0.0116 | 0.0156 | 0.7454 | 0.4662 |
Education | 0.0075 | 0.0082 | 0.914634 | 0.3768 |
Multiple regression equation:
y^ = (-0.8880) + (0.0350)Age + (0.0116)*income + (0.0075)*Education
b)
As the value of education increases by one unit , yearly purchase amount increases by 0.0075 on average keeping age and income constant.
c)
Null and alternative hypothesis:
Ho: β1= β2 = β3 = 0
Ha: at least oneβ ≠ 0
Test statistic:
F = 72.2478
P-value = =F.DIST.RT(72.2478,3,17) = 0.000
As p-value < 0.01, so we reject the null hypothesis.
This model is useful in predicting the yearly purchase at α = 0.01.