In: Statistics and Probability
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the following data have been gathered. Assume the degrees of freedom are 36. (Assume unequal variance)
Sample 1 |
Sample 2 |
|
Downtown Store |
North Mall Store |
|
n |
25 |
20 |
xbar |
$9 |
$9 |
s |
$2 |
$1 |
Q. What is a point estimate for the difference between the population means?
Q. What is the critical value for a 95% confidence interval for the difference between the two populations means?
Q. What is the margin of error for a 95% confidence interval for the difference between the two population means? (Provide 2 decimals)
Q. What is the 95% confidence interval for the difference between the two populations means?
Lower limit = (Provide 2 decimals)
Upper limit = (Provide 2 decimals)
a) point estimate = difference in sample means = x̅1-x̅2 = 9.000 - 9.0000 = 0.0000
b)
Degree of freedom, DF=
36
t-critical value = t α/2 =
2.028 (excel formula =t.inv(α/2,df)
c)
std error , SE = √(s1²/n1+s2²/n2) =
0.458
margin of error, E = t*SE = 2.028
* 0.458 = 0.93
4)
confidence interval is
Interval Lower Limit = (x̅1-x̅2) - E =
0.0000 - 0.929 =
-0.93
Interval Upper Limit = (x̅1-x̅2) + E =
0.0000 - 0.929 =
0.93
please revert for doubt..