Question

1. If the squirrel population of western MA has two alleles of a gene that determines coat color and 78% of the alleles in the population are the gray allele (the other 22% are the jet-black allele), then the gray allele is dominant over jet-black.

Select one:

a. False

b. True

2. You meet a woman who is heterozygous for an X-linked dominant disorder. If this woman has children, who will inherit this disorder from her?

Select one:

a. All of her daughters

b. Some of her sons and some of her daughters

c. Some of her daughters

d. All of her sons

e. Some of her sons

Answer 1

Ans1. True

As given information provided, the coat color are gray and jet- black in case of squirrel population of western MA. The population has 78% of gray alleles which represents either of heterozygous or homozygous alleles which are dominated in the population. And 22% are homozygous recessive which is why they are less in population. As from monohybrid cross of Mendel pea plant as example. The phenotypic ratio was 3:1. Which indicates 3 dominant genes over 1 recessive gene. Thus concluding that the gray coat color is the dominant in the population.

Ans2. (b) some of her sons and some of her daughters

Here in the question if the women having a X-linked dominant disorder has its children, they 50% of X- linked trait will be passed to the children. As the mother is heterozygous dominant for the trait. Only one X-linked allele will affect the children with disorders. Thus during segregation of alleles the mothers 50% of X- linked allele will be carried by both the sons and daughters and will show the disorders. And 50% will not have it.