Question

In: Accounting

The oil company located near Germany wants to install a new pipeline to connect a storage...

The oil company located near Germany wants to install a new pipeline to connect a storage tank to an existing pump 1,000 feet away. Three possible diameters are being considered to make the pipeline, the related costs of which are presented below:

The company is presumed to apply a 10% interest rate on its projects. Both maintenance and the annual cost of pumping are considered as expenses that occur at the end of the year (conventional flows).

For what number of pumping hours per year will the 4 and 6 inch pipelines be equally economical?

You must show in detail how you got your result. It is important that you submit the relevant evidence (cash flow equations, Excel, photo, etc.) in the link provided by this question for correction.

Pipeline diameter

4 pulg.

6 pulg.

8 pulg.

Initial cost

$2,000

$3,000

$4,000

Maintenance cost / year

600

500

400

Cost of pumping per hour

2.70

1.30

1.00

Residual value

100

150

300

Useful life (years)

10

10

10

Solutions

Expert Solution

Let us first see the PV Factors at 10%

Year PV Factor
0 1
1        0.909
2        0.826
3        0.751
4        0.683
5        0.621
6        0.564
7        0.513
8        0.467
9        0.424
10        0.386
       6.144

For 4 pulg.

Let number of hours be H

Present value = 2,000 + 600 X 6.144 + 2.70H X 6.144 - 100 X 0.386 = 16.5888 H + 5647.8

For 6 pulg

Let number of Hours be H

Present value = 3,000 + 500 X 6.144 + 1.30H X 6.144 - 150 X 0.386 = 7.9872 H + 6014.1

Since hours would be same

16.5888 H + 5647.8 = 7.9872 H + 6014.1
8.6061 H = 366.3
H = 42.5851 Hours

Here is the proof PV of both options is equal

Year PV Factor Amount Present value Amount Present value
0 1 2000 2000 3000 3000
1        0.909 714.9797712 649.916612 555.3606306 504.8228132
2        0.826 714.9797712 590.573291 555.3606306 458.7278809
3        0.751 714.9797712 536.9498082 555.3606306 417.0758336
4        0.683 714.9797712 488.3311837 555.3606306 379.3113107
5        0.621 714.9797712 444.0024379 555.3606306 344.8789516
6        0.564 714.9797712 403.248591 555.3606306 313.2233956
7        0.513 714.9797712 366.7846226 555.3606306 284.9000035
8        0.467 714.9797712 333.8955532 555.3606306 259.3534145
9        0.424 714.9797712 303.151423 555.3606306 235.4729074
10        0.386 614.9797712 237.3821917 405.3606306 156.4692034
       6.144 6354.235714 6354.235714

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