Question

In: Physics

Estimate the number of Solar neutrinos passing through a detector on the Earth in one second....

Estimate the number of Solar neutrinos passing through a detector on the Earth in one second. Assume that the detector has a surface area of 1.0 square meters and is aligned so that it faces directly towards the centre of the Sun. Assume that every neutrino travels without any change (i.e. none are absorbed or converted to a different particle). Also assume that the energy carried out of the Sun by the neutrinos is negligible

Solutions

Expert Solution

Answer: Number of solar neutrinos passing through detector per second are given by, N = 1015 neutrinos /s  


Explanation:

Neutrino is an Italian word as "little neutron" True to its name neutrino - a subatomic particle - is very tiny particle so it is difficult to detect this particle. It has zero electrical charge and very small rest mass. It was coined by Italian physicist Enrico Fermi and it is abundant but still very elusive particles. in order to explain the unaccountable energy and unaccountable angular momentum in beta decay, the existence of neutrinos was predicted by Great Physicist Wolfgang Pauli, later Fermi developed a sound theory of neutrinos.By Clyde L. Cowan and Frederick Reines of Los Alamos National Laboratory, Neutrinos were experimentally detected in 1956

The value of n = 1011 neutrions/(cm2.s) - which is nothing but number of solar neutrinos arriving at the Earth's surface per square centimetre per second

Let 1 m2 = 104 cm2

Let n = number of solar neutrinos arriving at the Earth's surface = 1011 neutrinos /(cm2.s)

Let A = area of detector = 1 m2 = 104 cm2

Let N = number of solar neutrinos passing through detector per second = n x A

Let N = n x A = 1011 neutrinos /(cm2.s) x 104 cm2 = 1015 neutrinos /s  

N - number of solar neutrinos passing through detector per second - are given by:

N = n x A = 1011 neutrinos /(cm2.s) x 104 cm2 = 1015 neutrinos /s  

N = 1015 neutrinos /s  ------------------------------------------------(answer)

Answer: Number of solar neutrinos passing through detector per second are given by, N = 1015 neutrinos /s


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