In: Statistics and Probability
Lynn Price recently completed her MBA and accepted a job with an electronics manufacturing company. Although she likes her job, she is also looking forward to retiring one day. To ensure that her retirement is comfortable, Lynn intends to invest $3,000 of her salary into a tax-sheltered retirement fund at the end of each year. Lynn is not certain what rate of return this investment will earn each year, but she expects each year’s rate of return could be modeled appropriately as a normally distributed random variable with a mean of 12.5% and standard deviation of 2%. (this problem requires the use of Analytic Solver Platform)
If Lynn is 30 years old, how much money should she expect to have in her retirement fund (expected value) at age 60? Answer this question by using the appropriate Psi Statistical function
What is the probability that Lynn will have more than $1 million in her retirement fund when she reaches age 60? Answer this question by using the appropriate Psi Statistical function
Attach the screenshots of your spreadsheet model and the distribution graph for the fund she will have at age 60
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Answer:
In accordance with the informatino available with in the data conditions, the expected mean value of the interest rate is 12.5% and the standard deviation of the interest rate is 2%
The expected investment that Lyn want to make there in the tax sheltered retirement fund is $3000.
Following is the table that indicate these interest rates,
Formula for simulation is PsiNormal(0.125,0.02)
Values obtianed are as follows,
S.No |
Interest |
1 |
12.5 |
2 |
13.44 |
3 |
13.83 |
4 |
10.24 |
5 |
14.54 |
6 |
12.88 |
7 |
15.63 |
8 |
17.39 |
9 |
15.54 |
10 |
14 |
11 |
15.52 |
12 |
13.84 |
13 |
12.06 |
14 |
13.32 |
15 |
13.08 |
16 |
14.06 |
17 |
16.34 |
18 |
11.74 |
19 |
12.41 |
20 |
13.1 |
21 |
11.54 |
22 |
13.1 |
23 |
13.77 |
24 |
13.94 |
25 |
10.59 |
26 |
11.43 |
27 |
19.5 |
28 |
8.66 |
29 |
11.43 |
30 |
13.39 |
31 |
9.92 |
Based on above simulated interest return values,
Balance can be found as follows,
S.No |
Age |
Balance$ |
Contribution$ |
Investment return |
Interest$ |
Balance$ |
1 |
0 |
3000 |
12.5 |
0 |
3000 |
|
2 |
3000 |
3000 |
13.44 |
403.2 |
6403.2 |
|
3 |
6403.2 |
3000 |
13.83 |
885.5626 |
10288.76 |
|
4 |
10288.76 |
3000 |
10.24 |
1053.569 |
14342.33 |
|
5 |
14342.33 |
3000 |
14.54 |
2085.375 |
19427.71 |
|
6 |
19427.71 |
3000 |
12.88 |
2502.289 |
24930 |
|
7 |
24930 |
3000 |
15.63 |
3896.558 |
31826.55 |
|
8 |
31826.55 |
3000 |
17.39 |
5534.638 |
40361.19 |
|
9 |
40361.19 |
3000 |
15.54 |
6272.129 |
49633.32 |
|
10 |
49633.32 |
3000 |
14 |
6948.665 |
59581.99 |
|
11 |
59581.99 |
3000 |
15.52 |
9247.124 |
71829.11 |
|
12 |
71829.11 |
3000 |
13.84 |
9941.149 |
84770.26 |
|
13 |
84770.26 |
3000 |
12.06 |
10223.29 |
97993.55 |
|
14 |
97993.55 |
3000 |
13.32 |
13052.74 |
114046.3 |
|
15 |
114046.3 |
3000 |
13.08 |
14917.26 |
131963.5 |
|
16 |
131963.5 |
3000 |
14.06 |
18554.07 |
153517.6 |
|
17 |
153517.6 |
3000 |
16.34 |
25084.78 |
181602.4 |
|
18 |
181602.4 |
3000 |
11.74 |
21320.12 |
205922.5 |
|
19 |
205922.5 |
3000 |
12.41 |
25554.99 |
234477.5 |
|
20 |
234477.5 |
3000 |
13.1 |
30716.55 |
268194.1 |
|
21 |
268194.1 |
3000 |
11.54 |
30949.59 |
302143.7 |
|
22 |
302143.7 |
3000 |
13.1 |
39580.82 |
344724.5 |
|
23 |
344724.5 |
3000 |
13.77 |
47468.56 |
395193 |
|
24 |
395193 |
3000 |
13.94 |
55089.91 |
453282.9 |
|
25 |
453282.9 |
3000 |
10.59 |
48002.66 |
504285.6 |
|
26 |
504285.6 |
3000 |
11.43 |
57639.85 |
564925.5 |
|
27 |
564925.5 |
3000 |
19.5 |
110160.5 |
678085.9 |
|
28 |
678085.9 |
3000 |
8.66 |
58722.24 |
739808.2 |
|
29 |
739808.2 |
3000 |
11.43 |
84560.07 |
827368.2 |
|
30 |
827368.2 |
3000 |
13.39 |
110784.6 |
941152.8 |
|
31 |
941152.8 |
3000 |
9.92 |
93362.36 |
1037515 |
Average = $900,565 and the std dev = $70,084
B. The probability that Lyn can have more than >1,000,000 in her retirement funding is 0.085 ---------------(aT AGE 60 year)