In: Operations Management
A manufacturing facility replaces its industrial light fixtures at a rate of 100 units per day. The plant orders the lights periodically and it costs $100 to initiate a purchase order. A light unit kept in storage is estimated to cost about $.02 per day. The lead time between placing and receiving an order is 12 days. Determine the optimal inventory policy for ordering and include the order quantity, frequency of orders (in days), reorder point (in units) and expected non purchase costs associated with this order practice (per day).
Solution:
It is given that –
To optimize total cost (ordering and holding costs), Economic Order Quantity would be:
Q =
=
= 1,000 units per order ANSWER
Frequency of order (in days)would be:
N = Order quantity / Demand per day
= Q / D
= 1,000 / 100
= 10 Days ANSWER
Now it is also given that the lead time = L = 12 days
Please note that this is a case, in which order lead time (12 days) is more than one order cycle (10 days), but less than two order cycles (20 days). Hence the reorder will happen one order cycle advance and the reorder level would be would be:
R = (Order lead time * Demand per day) – Order quantity
= (L * D) - Q
= (12 * 100) – 1,000
= 200 units ANSWER
This reorder level can be graphically shown as below:
Now minimum inventory = 0 units
And maximum inventory = Q = 1000 units
So, the average inventory would be = ( 0 + 1000 ) / 2 = 500
So expected non purchase cost will be the inventory holding cost per day, i.e.
Inventory holding cost = average inventory * holding cost per unit
= 500 * 0.02 = $ 10 per day ANSWER
ANSWER: The inventory policy (as shown graphically above) will be as follows:
Ordering Quantity = 1,000 units per order
Ordering frequency = 10 days
Reorder level = 200 units
Non purchase costs (holding costs) = $ 10 per day