Question

In: Statistics and Probability

The following table summarizes results from 985 pedestrian deaths that were caused by accidents (based on...

The following table summarizes results from 985 pedestrian deaths that were caused by accidents (based on data from the National Highway Traffic Safety Administration).

If the pedestrian was intoxicated, find the probability that the driver was intoxicated. Round to two decimals.

pedestrian intoxicated
yes no
driver intoxicated yes 59 79
no 266 581

Solutions

Expert Solution

The data is given in the table below.

Pedestrian Intoxicated Total
Yes No
Driver Intoxicated Yes 59 79 138
No 266 581 847
Total 325 660 985

P(driver was intoxicated | pedestrian was intoxicated) = P(driver and pedestrian were intoxicated) / P(pedestrian was intoxicated)       ............(conditional probability)

P(driver and pedestrian were intoxicated) = 59 / 985                                                             

P(pedestrian was intoxicated) = 325 / 985

P(driver was intoxicated | pedestrian was intoxicated) = (59 / 985) / (325 / 985)

                                                                                          = 59 / 325

                                                                                          = 0.1815

Therefore, if the pedestrian was intoxicated, the probability that the driver was intoxicated is 0.18


Related Solutions

The Titanic Used the data in the following table, which summarizes results from the sinking of...
The Titanic Used the data in the following table, which summarizes results from the sinking of the titanic. Men Women Boys Girls Survived 332 318 29 27 Died 1360 104 35 18 If one of the Titanic passengers is randomly selected, find the probability of getting someone who is a women or survivor. If one of the Titanic passengers is randomly selected, find the probability of getting a man and someone who survived the sinking. If one of the Titanic...
The following table summarizes the results from a two-factor study with 3 levels of Factor A...
The following table summarizes the results from a two-factor study with 3 levels of Factor A and 4 levels of Factor B using a separate sample of 5 participants in each treatment condition. Fill in the missing values. Make sure to show your work. Source SS df MS F Between treatments 650 Factor A 5 0 Factor B AxB interaction 120 Within treatments 2 5 Total
A study involves 605 randomly selected deaths, with 28 of them caused by accidents. Use this...
A study involves 605 randomly selected deaths, with 28 of them caused by accidents. Use this data to construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents.
Use the data in the accompanying table that summarizes results from a clinical trial of a...
Use the data in the accompanying table that summarizes results from a clinical trial of a drug. Let A = Drug Treatment, B = Placebo headache No Headache total Drug Treatment (A) 122 585 707 Placebo ( B) 28 672 700 Total 150 1257 1407 Answer the following: 1. Find the probability that patient under treatment p(A) 2. Find p(B) 3. Find the probability a patient has a headache 4. Find the probability a patient has a headache and he...
a study involves 612 randomly selected deaths, with 29 caused by accidents. Construct a 98% confidence...
a study involves 612 randomly selected deaths, with 29 caused by accidents. Construct a 98% confidence interval for the percentage of all deaths that are caused by accidents.
Write an analysis (essay) for question 2) The table summarizes the results from an observational study...
Write an analysis (essay) for question 2) The table summarizes the results from an observational study that followed a random sample of 8,474 people for about four years. All participants were free from heart disease at the beginning of the study. The variable Anger categorizes participants as Low Anger, Moderate Anger, High Anger based on the Speilberger Trait Anger Scale test, which measures how prone a person is to sudden feelings of anger. CHD stands for coronary heart disease, which...
An Excel ANOVA table that summarizes the results of an experiment to assess the effects of...
An Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. Source of Variation SS df MS F P-value F crit Plant location 3.0075 3 1.0025 2.561 0.1199 3.862 Noise level 8.4075 3 2.8025 7.160 0.0093 3.863 Error 3.5225 9 0.3914 Total 14.9375 State the 2 null hypothesis for the F statistics listed above At the 1% significance level, do you reject or fail to reject...
Among all the car accidents last year, 492 deaths were reported in the road of which...
Among all the car accidents last year, 492 deaths were reported in the road of which 240 wore belts and 252 wore no belts. Of the 2334 people involved in serious accidents 1945 wore seat belts and the rest no to. Calculate the probability of dying by not wearing a belt b. Calculate the probability of dying if you wear the belt c. If a person dies in a car accident; What is the probability of who will wear a...
The table shows the number of manatee deaths caused by watercraft in Florida each year beginning...
The table shows the number of manatee deaths caused by watercraft in Florida each year beginning in 1980. The years are coated that 1980 is 1, 1981 is 2, and so on. Use the table to find the best model and the R2 value. Year 1 2 3 4 5 6 7 8 9 10 Deaths 16 24 20 15 34 33 33 39 43 50 A. linear model, 0.845 B. exponential model, 0.779 C. power model, 0.682 D. quadratic...
The following table summarizes some of the results in the meta-analysis for smokers who used e-cigarettes...
The following table summarizes some of the results in the meta-analysis for smokers who used e-cigarettes with nicotine. total Sample Number who stopped smoking Study 1 464 93 Study 2 289 21 Study 3 200 22 Study 4 35 16 Study 5 40 5 Study 6 214 67 Answer the following questions: Find the total number of smokers in all six studies and the total number who stopped smoking. Find a new confidence interval for the proportion of smokers who...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT