The Chi Square test which allows you to compare frequencies of groups! So back in the...

The Chi Square test which allows you to compare frequencies of groups! So back in the day, the Mars Candy company claimed that there were 13% brown, 14% yellow, 13% red, 24% blue, 20% orange and 16% green. We can use a chi square test to test this frequency claim.

Use hypothetical data for a bag of M&M candy.

What is the Ho hypothesis?

What is the H1 hypothesis?

What is our expected value?

What is our observed value? Use the data below!

What is our degree of freedom? (because we are comparing the different colors, each color is counted as a category).

What is the chi square value?

Expected:

13% brown,

14% yellow,

13% red,

24% blue,

20% orange

16% green

Observed (counted number):

12 brown,

15 yellow,

25 red,

10 blue,

5 orange

16 green

Was it significant?

What is your favorite color of M&M?

Solutions

Expert Solution

Ho: distribution is same as expected
Ha: distribution is different from expected

observed frequencey, O	expected proportion	expected frequency,E	(O-E)	(O-E)²	(O-E)²/E
12	0.130	10.79	1.21	1.46	0.136
15	0.140	11.62	3.38	11.42	0.983
25	0.130	10.79	14.21	201.92	18.714
10	0.240	19.92	-9.92	98.41	4.940
5	0.200	16.60	-11.60	134.56	8.106
16	0.160	13.280	2.72	7.40	0.557

chi square test statistic,X² = Σ(O-E)²/E =   33.436

l
Degree of freedom=k-1=   6   -   1   =   5

P value =   0.000   [ excel function: =chisq.dist.rt(test-stat,df) ]
Decision: P value < α, Reject Ho

orchestra answered 1 year ago

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