In: Statistics and Probability
Assume that a researcher is interested in testing whether there is a significant effect of video game playing on teenagers’ visual-spatial abilities. The researcher randomly selects 4 participants and measures their visual-spatial cognition before and after playing video games for 4 hours a day for a week.*SHOW WORK FOR THIS PROBLEM.
a. Use the data in the table below to conduct the appropriate statistical test including all of the necessary steps. Assume α = .10.
Participant |
Xbefore | Xafter |
A |
85 |
86 |
B |
78 |
85 |
C |
96 |
97 |
D |
68 |
72 |
1) H0: µD , H1: µD
2) tcrit = (DO NOT ROUND)
3) t = (ROUND TO THREE DECIMALS)
4) Decision = (FTR or RTN)
b. Also construct a 90% confidence interval of the difference.
90%CI(,) (ROUND TO TWO DECIMALS)
Number | Before | After | Difference | |
85 | 86 | -1 | 5.0625 | |
78 | 85 | -7 | 14.0625 | |
96 | 97 | -1 | 5.0625 | |
68 | 72 | -4 | 0.5625 | |
Total | 327 | 340 | -13 | 24.75 |
To Test :-
H0 :-
H1 :-
Critical values
Test Statistic :-
t = -2.263
Test Criteria :-
Reject null hypothesis if
= 2.263 < 2.353
Result :- Fail to reject null hypothesis
Decision based on P value
P - value = P ( t > 2.263 ) = 0.1086
Reject null hypothesis if P value <
level of significance
P - value = 0.1086 > 0.1 ,hence we fail to reject null
hypothesis
Conclusion :- Fail to reject null
hypothesis
Part b)
Confidence Interval :-
Lower Limit =
Lower Limit = -6.63
Upper Limit =
Upper Limit = 0.13
90% Confidence interval is ( -6.63 , 0.13
)