In: Physics
A small mailbag is released from a helicopter that is descending steadily at 1.69 m/s.
(a) After 3.00 s, what is the speed of the mailbag?
v = m/s
(b) How far is it below the helicopter?
d = m
(c) What are your answers to parts (a) and (b) if the helicopter is
rising steadily at 1.69 m/s?
v = m/s |
d = m |
Use equation of kinematics for vertical motion under influence of gravity where downward is the positive direction as shown below
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This concludes the answers. If there is any mistake or
omission, let me know in the comments immediately and I will fix
it....