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Weekly production schedules are needed for the manufacture of two products X and Y. Each unit...

Weekly production schedules are needed for the manufacture of two products X and Y. Each unit of X uses one component made in the factory, while each unit of Y uses two of the components, and the factory has a maximum output of 80 components a week. Each unit of X and Y requires 10 hours of subcontracted work and agreements have been signed with subcontractors for a minimum weekly usage of 200 hours and a maximum weekly usage of 600 hours. The marketing department says that all production of Y can be sold but there is a maximum demand of 50 units of X, despite a long-term contract to supply 10 units of X to one customer. The net profit on each unit of X and Y is $200 and $300 respectively.

Linnear Programming step by step, show work manually without using excel, Include a graph, and corner. I would like to try to understand how the question is done step by step. Thank you so much

Solutions

Expert Solution

Let the weekly production are needed for the manufacture of two products X and Y be x units and y units respectively.

Then by the given conditions we have,

Maximize Z = 200x+300y

Subject to x+2y 80

10x+10y 200

10x+10y 600

x 50

x,y 0

i.e., Maximize Z = 200x+300y

Subject to x+2y 80

x+y 20

x+y 60

x 50

x,y 0

Introducing slack variables a,c,d and surplus variable b the problem becomes,

Maximize Z = 200x+300y+0a+0b+0c+0d

Subject to x+2y+a = 80

x+y-b = 20

x+y+c = 60

x+d = 50

x,y,a,b,c,d 0

COMPUTATION TABLE :

cj 200 300 0 0 0 0
cB B b a1 a2 a3 a4 a5 a6
0 a3 80 1 2 1 0 0 0
0 a4 20 1 1 0 -1 0 0
0 a5 60 1 1 0 0 1 0
0 a6 50 1 0 0 0 0 1
zj-cj -200 -300 0 0 0 0
0 a3 40 -1 0 1 2 0 0
300 a2 20 1 1 0 -1 0 0
0 a5 40 0 0 0 1 1 0
0 a6 50 1 0 0 0 0 1
zj-cj 100 0 150 -300 0 0
0 a3 20 -1/2 0 1/2 1 0 0
300 a2 40 1/2 1 1/2 0 0 0
0 a4 20 1/2 0 -1/2 0 1 0
0 a6 50 1 0 0 0 0 1
zj-cj -50 0 150 0 0 0
0 a3 40 0 0 0 1 1 0
300 a2 20 0 1 1 0 -1 0
200 a1 40 1 0 -1 0 2 0
0 a6 10 0 0 1 0 2 1
zj-cj 0 0 100 0 100 0

In the last tableau all zj-cj 0.

The optimal solution is : x = 40, y = 20 and Zmax = (200*40)+(300*20) = 14000

Therefore, the weekly production are needed for the manufacture of two products X and Y are 40 units and 20 units respectively and total profit is $14000.


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