Question

In: Finance

You can jump to a height of 2.6625 ft (0.81153 m) on Earth. If you expend the same energy jumping on

You can jump to a height of 2.6625 ft (0.81153 m) on Earth. If you expend the same energy jumping on the moon where the acceleration of gravity is only 1.6 m/s2, how high would you rise?

Solutions

Expert Solution

On earth, the energy you have when you reach the top of your flight is potential energy defined as "mgh" where "m" is your mass, "g" is the acceleration due to gravity on earth and is 9.81 m/s2 and h = 0.81153 meters

So mgh = m(9.81)(0.81153) = 7.9611m

 

On the moon, you also want to expend the same amount of energy or 7.9611m so:

7.9611m = mgh where "m" is your mass, "g" is the acceleration due to gravity on the moon and is given as 1.6 m/s2 so:

7.9611m = m(1.6)h

Dividing both sides by "m":

7.9611 = 1.6h

h = 5.0 meters (you are given the acceleration due to gravity on the moon in 2 sig figs so we round to 2 sig figs)

 


h = 5.0 meters (you are given the acceleration due to gravity on the moon in 2 sig figs so we round to 2 sig figs)

Related Solutions

A flea can jump straight up to a height of 22.0 cm
A flea can jump straight up to a height of 22.0 cm.(a) What is its initial speed (in m/s) as it leaves the ground, neglecting air resistance?(b) How long is it in the air?(c) What are the magnitude and direction of its acceleration while it isi. moving upward?ii. moving downward?iii. at the highest point?
Would you agree that a C3 plant has to expend more energy per molecule of CO2...
Would you agree that a C3 plant has to expend more energy per molecule of CO2 converted to carbohydrate than a C4 plant? Why or why not?
As you have seen, lead can form the same kinds of compounds as the alkaline earth...
As you have seen, lead can form the same kinds of compounds as the alkaline earth metals. Nevertheless, the solubilities may differ markedly. Give a convincing reason.
Locusts can jump to heights of 0.870 m. The locust actually jumps at an angle of...
Locusts can jump to heights of 0.870 m. The locust actually jumps at an angle of about 55.0° to the horizontal, and air resistance is not negligible. The result is that the takeoff speed is about 40.0% higher than the takeoff speed when the locust jumps straight up, and ignoring air resistance. If the mass of the locust is 2.00 g and its body moves 4.00 cm in a straight line while accelerating from rest to the takeoff speed, calculate...
Locusts can jump to heights of 0.680 m The locust actually jumps at an angle of...
Locusts can jump to heights of 0.680 m The locust actually jumps at an angle of about 55 degrees to the horizontal, and air resistance is not eligible. The result is that the take-off speed is about 40.0% higher than the speed when the locust jumps straight up and ignoring air resistance. If the mass of the locust is 2.00 g and it's body moves 4.00 cm in a straight line while accelerating from rest to the takeoff speed. A....
1) You can jump 3 m (10 feet) off of a diving board and into a swimming pool and be uninjured.
  1) You can jump 3 m (10 feet) off of a diving board and into a swimming pool and be uninjured. However, if you jumped from the same height onto concrete it would be very bad. Use the principles of impulse and momentum to explain this. 2) A 125 kg linebacker running to the right at 2.5 m/s and an 80 kg quarterback running to the left at 3 m/s collide in midair. The linebacker holds on to the...
Can you use the same variational wave function as in (2) to determine the energy of...
Can you use the same variational wave function as in (2) to determine the energy of the first excited state of the one-dimensional harmonic oscillator? Why or why not?
If it has enough kinetic energy, a molecule at the surface of the Earth can escape...
If it has enough kinetic energy, a molecule at the surface of the Earth can escape the Earth’s gravitation. The acceleration of gravity is 9.8 m/s2, and the Boltzmanns’ constant is 1.38066 × 10−23 J/K. minimum kinetic energy needed to escape in terms of the mass of the molecule m, the free-fall acceleration at the surface g, and the radius of the Earth R. 1. Kmin = 1 m g R 3 2. Kmin = 1mgR 2    3. Kmin...
can two satellites with different masses have the same orbit around the earth?
can two satellites with different masses have the same orbit around the earth?
Calculate the work needed for a bird of mass 120 g to fly to a height of 50 m from the surface of the Earth
Calculate the work needed for a bird of mass 120 g to fly to a height of 50 m from the surface of the Earth.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT