In: Accounting
Solution: | ||||
Answer is 2nd option $21,675 | ||||
Working Notes: | ||||
Depreciation Expense for 1st year & 2nd year = (Cost - Salvage value )/ life | ||||
Depreciation Expense for 1st year & 2nd year = (109,000 - 12,500 )/10 | ||||
Depreciation Expense for 1st year & 2nd year =9,650 per year | ||||
Hence, | Depreciation already charged till 3rd year before 3rd year Depreciation. | = 2 x Depreciation per year | ||
= 2 x 9650 | ||||
=$19,300 | ||||
At end of 3rd year | Revised book value = Cost - Depreciation charged till 3rd year | |||
Revised book value = $109,000 - $19300 | ||||
Revised book value = $89,700 | ||||
Revised residual value =$3,000 | ||||
Revised life= 4 years | ||||
Revised depreciation per year = (Revised book value - Revised residual value )/Revised life | ||||
Revised depreciation per year = ($89,700 - $3,000 )/4 | ||||
Revised depreciation per year = $86,700/4 | ||||
Revised depreciation per year = $21,675 | ||||
Hence , Depreciation Expense for 3rd year is $21,675 | ||||
Notes: | Deprecation Expense for each 3rd year & 4th , 5th, 6th years are $21,675 will be equal as per straight line method | |||
Please feel free to ask if anything about above solution in comment section of the question. |