Question

The following are the body temperatures (in °F) of randomly selected normal, healthy adults:

98.6     98.6     98.0     98.0     99.0     98.4     98.4     98.4     98.4     98.6

Range and Standard Deviation. Exercises each provide a set of numbers. In each case, find the range and standard deviation.

Answer 1

98.6     98.6     98.0     98.0     99.0     

98.4     98.4     98.4     98.4     98.6

 

n = 10

Range in the difference of maximum & the minimum number.

Range = (99.0 – 98.0) °F

Range = 1.0 °F

 

Before calculating standard deviation, we first need to calculate mean as:

 

x̅ = 98.6 + 98.6 + 98.0 + … + 98.4 + 98.6/10

= 98.44 °F

 

Now, standard deviation,

 

s = √Σni=1 (xi - x̅)2/n – 1

= √[{(98.6 – 98.44)2 + (98.6 – 98.44)2 + … + (98.6 – 98.44)2}/10 – 1]

= 0.2951

 

∴ standard deviation, s = 0.2951°F

Range = 1.0 °F

∴ standard deviation, s = 0.2951°F